SRM 630 DIV2
The first time I tried TC, I thought I had AK, but the 1000 points were still lost by the system, but I also lost the room and other people made a lot of money
A: The length of the string is only 50, you can simply simulate it directly
B: The number of nodes is only 10. First do one floyd to find the path between the two, and then violently enumerate which points to choose to determine whether it is possible. If If possible, record the maximum number
C: The initial approach is to construct the rank array, put a in each consecutive segment, and then put b in the last one, thinking that what is constructed in this way must be a dictionary. The one with the smallest sequence was eventually deleted by the system.
Correct approach: Construct the sa array at the beginning, and violently enumerate each position. If it is not 'a', just subtract 1 to ensure that the lexicographic order is small. Then construct the sa array and judge the two suffix arrays. If all positions are different, it means that this is the smallest dictionary order
Code:
A:
#include <cstdio>#include <cstring>#include <iostream>#include <vector>#include <set>#include <map>#include <string>using namespace std;class DoubleLetter { public: string ableToSolve(string S) { while (1) { int n = S.length(); string tmp = ""; int flag = 1; for (int i = 0; i <br> B: <p></p> <p> </p> <pre name="code" class="sycode">#include <iostream>#include <cstdio>#include <cstring>#include <vector>#include <algorithm>using namespace std;class Egalitarianism3Easy {public: int bitcount(int x) { int ans = 0; while (x) { ans += (x&1); x >>= 1; } return ans; } int maxCities(int n, vector<int> a, vector<int> b, vector<int> len) { int g[15][15]; for (int i = 1; i <br> C: <p></p> <p> </p> <pre name="code" class="sycode">#include <iostream>#include <cstdio>#include <string>#include <algorithm>using namespace std;typedef pair<string int> pii;class SuffixArrayDiv2 { public: string smallerOne(string s) { int n = s.length(); pii save[55]; for (int i = n - 1; i >= 0; i--) { string tmp = ""; for (int j = i; j = 0; i--) { string tmp = ""; for (int j = i; j <br> <br> <p></p> </string></algorithm></string></cstdio></iostream>

HTMLisnotaprogramminglanguage;itisamarkuplanguage.1)HTMLstructuresandformatswebcontentusingtags.2)ItworkswithCSSforstylingandJavaScriptforinteractivity,enhancingwebdevelopment.

HTML is the cornerstone of building web page structure. 1. HTML defines the content structure and semantics, and uses, etc. tags. 2. Provide semantic markers, such as, etc., to improve SEO effect. 3. To realize user interaction through tags, pay attention to form verification. 4. Use advanced elements such as, combined with JavaScript to achieve dynamic effects. 5. Common errors include unclosed labels and unquoted attribute values, and verification tools are required. 6. Optimization strategies include reducing HTTP requests, compressing HTML, using semantic tags, etc.

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WebdevelopmentreliesonHTML,CSS,andJavaScript:1)HTMLstructurescontent,2)CSSstylesit,and3)JavaScriptaddsinteractivity,formingthebasisofmodernwebexperiences.

The role of HTML is to define the structure and content of a web page through tags and attributes. 1. HTML organizes content through tags such as , making it easy to read and understand. 2. Use semantic tags such as, etc. to enhance accessibility and SEO. 3. Optimizing HTML code can improve web page loading speed and user experience.

HTMLisaspecifictypeofcodefocusedonstructuringwebcontent,while"code"broadlyincludeslanguageslikeJavaScriptandPythonforfunctionality.1)HTMLdefineswebpagestructureusingtags.2)"Code"encompassesawiderrangeoflanguagesforlogicandinteract

HTML, CSS and JavaScript are the three pillars of web development. 1. HTML defines the web page structure and uses tags such as, etc. 2. CSS controls the web page style, using selectors and attributes such as color, font-size, etc. 3. JavaScript realizes dynamic effects and interaction, through event monitoring and DOM operations.

HTML defines the web structure, CSS is responsible for style and layout, and JavaScript gives dynamic interaction. The three perform their duties in web development and jointly build a colorful website.


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