search
HomeWeb Front-endHTML TutorialCodeforces Round #277.5 (Div. 2)_html/css_WEB-ITnose

A. SwapSort

time limit per test

1 second

memory limit per test

256 megabytes

input

standard input

output

standard output

In this problem your goal is to sort an array consisting of n integers in at most n swaps. For the given array find the sequence of swaps that makes the array sorted in the non-descending order. Swaps are performed consecutively, one after another.

Note that in this problem you do not have to minimize the number of swaps ? your task is to find any sequence that is no longer than n.

Input

The first line of the input contains integer n (1?≤?n?≤?3000) ? the number of array elements. The second line contains elements of array: a0,?a1,?...,?an?-?1 (?-?109?≤?ai?≤?109), where ai is the i-th element of the array. The elements are numerated from 0 to n?-?1 from left to right. Some integers may appear in the array more than once.

Output

In the first line print k (0?≤?k?≤?n) ? the number of swaps. Next k lines must contain the descriptions of the k swaps, one per line. Each swap should be printed as a pair of integers i, j (0?≤?i,?j?≤?n?-?1), representing the swap of elements ai and aj. You can print indices in the pairs in any order. The swaps are performed in the order they appear in the output, from the first to the last. It is allowed to print i?=?jand swap the same pair of elements multiple times.

If there are multiple answers, print any of them. It is guaranteed that at least one answer exists.

Sample test(s)

input

55 2 5 1 4

output

20 34 2

input

610 20 20 40 60 60

output

input

2101 100

output

1<p>0 1</p><p></p><p></p><pre name="code" class="n">#include <iostream>#include <cstdio>#include <cstring>#include <algorithm>using namespace std;int a[3010];int b[120];int vis[120];typedef pair<int> P;P m[3010];int main(){   #ifdef xxz    freopen("in.txt","r",stdin);    #endif // [xxz    int n;    cin>>n;    for(int i = 0; i >a[i];    int sum = 0,ans = 0;    int i,j;    for(i = 0; i  a[j])           {                x = a[j];                y = j;           }        }        if(y != i)        {            m[sum].first = i;            m[sum++].second = y;            swap(a[i],a[y]);            ans++;        }    }    cout<br><p></p>                      <p class="sycode">                          </p>
<p class="sycode">        </p>
<p class="sycode">         </p>
<p class="sycode">          </p>
<p class="sycode">           </p>
<p class="sycode">            </p>
<p class="sycode">             B. BerSU Ball            </p>            <p class="sycode">             </p>
<p class="sycode">              time limit per test             </p>1 second                        <p class="sycode">             </p>
<p class="sycode">              memory limit per test             </p>256 megabytes                        <p class="sycode">             </p>
<p class="sycode">              input             </p>standard input                        <p class="sycode">             </p>
<p class="sycode">              output             </p>standard output                                  <p class="sycode">            </p>
<p>The Berland State University is hosting a ballroom dance in celebration of its 100500-th anniversary! n boys and m girls are already busy rehearsing waltz, minuet, polonaise and quadrille moves.</p>            <p>We know that several boy&girl pairs are going to be invited to the ball. However, the partners' dancing skill in each pair must differ by at most one.</p>            <p>For each boy, we know his dancing skills. Similarly, for each girl we know her dancing skills. Write a code that can determine the largest possible number of pairs that can be formed from n boys and m girls.</p>                      <p class="sycode">            </p>
<p class="sycode">             Input            </p>            <p>The first line contains an integer n (1?≤?n?≤?100) ? the number of boys. The second line contains sequence a1,?a2,?...,?an (1?≤?ai?≤?100), where ai is the i-th boy's dancing skill.</p>            <p>Similarly, the third line contains an integer m (1?≤?m?≤?100) ? the number of girls. The fourth line contains sequence b1,?b2,?...,?bm (1?≤?bj?≤?100), where bj is the j-th girl's dancing skill.</p>                      <p class="sycode">            </p>
<p class="sycode">             Output            </p>            <p>Print a single number ? the required maximum possible number of pairs.</p>                      <p class="sycode">            </p>
<p class="sycode">             Sample test(s)            </p>            <p class="sycode">             </p>
<p class="sycode">              </p>
<p class="sycode">               input              </p>              <pre style="代码" class="n">41 4 6 255 1 5 7 9

output

input

41 2 3 4410 11 12 13

output

input

51 1 1 1 131 2 3

output


#include <iostream>#include <cstdio>#include <cstring>#include <algorithm>using namespace std;int a[120];int b[120];int vis[120];int main(){   #ifdef xxz    freopen("in.txt","r",stdin);    #endif // [xxz    int n,m;    cin>>n;    for(int i = 0; i >a[i];    sort(a,a+n);    cin>>m;    for(int i = 0; i >b[i],vis[i] = 0;    sort(b,b+m);    int sum = 0;    int j;    for(int i =0; i <br>                      <p class="sycode">                          </p>
<p class="sycode">        C. Given Length and Sum of Digits...       </p>                          <p class="sycode">        </p>
<p class="sycode">         time limit per test        </p>1 second                                 <p class="sycode">        </p>
<p class="sycode">         memory limit per test        </p>256 megabytes                                 <p class="sycode">        </p>
<p class="sycode">         input        </p>standard input                                 <p class="sycode">        </p>
<p class="sycode">         output        </p>standard output                                                   <p class="sycode">                          </p>
<p>You have a positive integer m and a non-negative integer s. Your task is to find the smallest and the largest of the numbers that have length m and sum of digits s. The required numbers should be non-negative integers written in the decimal base without leading zeroes.</p>                                            <p class="sycode">                          </p>
<p class="sycode">        Input       </p>                          <p>The single line of the input contains a pair of integers m, s (1?≤?m?≤?100,?0?≤?s?≤?900) ? the length and the sum of the digits of the required numbers.</p>                                            <p class="sycode">                          </p>
<p class="sycode">        Output       </p>                          <p>In the output print the pair of the required non-negative integer numbers ? first the minimum possible number, then ? the maximum possible number. If no numbers satisfying conditions required exist, print the pair of numbers "-1 -1" (without the quotes).</p>                                            <p class="sycode">                          </p>
<p class="sycode">        Sample test(s)       </p>                          <p class="sycode">        </p>
<p class="sycode">         </p>
<p class="sycode">          input         </p>         <pre style="代码" class="n">2 15

output

69 96

input

3 0

output

-1 -1
#include <iostream>#include <algorithm>#include <cstdio>using namespace std;bool can(int m, int s){    if(s >= 0 && 9*m >= s) return true;    else return false;}int main(){    int m,s;    cin>>m>>s;    if(!can(m,s))    {        cout= 10)        {            cout 0 || (j == 0 && i > 1) ) && can(m - i, sum - j))                   {                       minn += char('0' + j);                       sum -= j;                       break;                   }            }            sum = s;               for(int i = 1; i = 0; j--)            {                if(can(m - i, sum - j))                   {                       maxn += char('0' + j);                       sum -= j;                       break;                   }            }            cout<br><br><p></p></cstdio></algorithm></iostream>
Statement
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
What is the difference between an HTML tag and an HTML attribute?What is the difference between an HTML tag and an HTML attribute?May 14, 2025 am 12:01 AM

HTMLtagsdefinethestructureofawebpage,whileattributesaddfunctionalityanddetails.1)Tagslike,,andoutlinethecontent'splacement.2)Attributessuchassrc,class,andstyleenhancetagsbyspecifyingimagesources,styling,andmore,improvingfunctionalityandappearance.

The Future of HTML: Evolution and TrendsThe Future of HTML: Evolution and TrendsMay 13, 2025 am 12:01 AM

The future of HTML will develop in a more semantic, functional and modular direction. 1) Semanticization will make the tag describe the content more clearly, improving SEO and barrier-free access. 2) Functionalization will introduce new elements and attributes to meet user needs. 3) Modularity will support component development and improve code reusability.

Why are HTML attributes important for web development?Why are HTML attributes important for web development?May 12, 2025 am 12:01 AM

HTMLattributesarecrucialinwebdevelopmentforcontrollingbehavior,appearance,andfunctionality.Theyenhanceinteractivity,accessibility,andSEO.Forexample,thesrcattributeintagsimpactsSEO,whileonclickintagsaddsinteractivity.Touseattributeseffectively:1)Usese

What is the purpose of the alt attribute? Why is it important?What is the purpose of the alt attribute? Why is it important?May 11, 2025 am 12:01 AM

The alt attribute is an important part of the tag in HTML and is used to provide alternative text for images. 1. When the image cannot be loaded, the text in the alt attribute will be displayed to improve the user experience. 2. Screen readers use the alt attribute to help visually impaired users understand the content of the picture. 3. Search engines index text in the alt attribute to improve the SEO ranking of web pages.

HTML, CSS, and JavaScript: Examples and Practical ApplicationsHTML, CSS, and JavaScript: Examples and Practical ApplicationsMay 09, 2025 am 12:01 AM

The roles of HTML, CSS and JavaScript in web development are: 1. HTML is used to build web page structure; 2. CSS is used to beautify the appearance of web pages; 3. JavaScript is used to achieve dynamic interaction. Through tags, styles and scripts, these three together build the core functions of modern web pages.

How do you set the lang attribute on the  tag? Why is this important?How do you set the lang attribute on the tag? Why is this important?May 08, 2025 am 12:03 AM

Setting the lang attributes of a tag is a key step in optimizing web accessibility and SEO. 1) Set the lang attribute in the tag, such as. 2) In multilingual content, set lang attributes for different language parts, such as. 3) Use language codes that comply with ISO639-1 standards, such as "en", "fr", "zh", etc. Correctly setting the lang attribute can improve the accessibility of web pages and search engine rankings.

What is the purpose of HTML attributes?What is the purpose of HTML attributes?May 07, 2025 am 12:01 AM

HTMLattributesareessentialforenhancingwebelements'functionalityandappearance.Theyaddinformationtodefinebehavior,appearance,andinteraction,makingwebsitesinteractive,responsive,andvisuallyappealing.Attributeslikesrc,href,class,type,anddisabledtransform

How do you create a list in HTML?How do you create a list in HTML?May 06, 2025 am 12:01 AM

TocreatealistinHTML,useforunorderedlistsandfororderedlists:1)Forunorderedlists,wrapitemsinanduseforeachitem,renderingasabulletedlist.2)Fororderedlists,useandfornumberedlists,customizablewiththetypeattributefordifferentnumberingstyles.

See all articles

Hot AI Tools

Undresser.AI Undress

Undresser.AI Undress

AI-powered app for creating realistic nude photos

AI Clothes Remover

AI Clothes Remover

Online AI tool for removing clothes from photos.

Undress AI Tool

Undress AI Tool

Undress images for free

Clothoff.io

Clothoff.io

AI clothes remover

Video Face Swap

Video Face Swap

Swap faces in any video effortlessly with our completely free AI face swap tool!

Hot Article

Hot Tools

Notepad++7.3.1

Notepad++7.3.1

Easy-to-use and free code editor

SecLists

SecLists

SecLists is the ultimate security tester's companion. It is a collection of various types of lists that are frequently used during security assessments, all in one place. SecLists helps make security testing more efficient and productive by conveniently providing all the lists a security tester might need. List types include usernames, passwords, URLs, fuzzing payloads, sensitive data patterns, web shells, and more. The tester can simply pull this repository onto a new test machine and he will have access to every type of list he needs.

MantisBT

MantisBT

Mantis is an easy-to-deploy web-based defect tracking tool designed to aid in product defect tracking. It requires PHP, MySQL and a web server. Check out our demo and hosting services.

ZendStudio 13.5.1 Mac

ZendStudio 13.5.1 Mac

Powerful PHP integrated development environment

SublimeText3 Chinese version

SublimeText3 Chinese version

Chinese version, very easy to use