1. 如何用php的环境变量得到一个网页地址的内容?ip地址又要怎样得到?
echo $_SERVER['PHP_SELF'];
echo $_SERVER['REMOTE_ADDR'];
?>
2. 求两个日期的差数,例如2007-2-5 ~ 2007-3-6 的日期差数
$begin=strtotime('2007-2-5);
$end=strtotime('2007-3-6);
echo ($end-$begin)/24*60*60;
?>
3. 请写一个函数,实现以下功能:
字符串“open_door” 转换成 “OpenDoor”、”make_by_id” 转换成 ”MakeById”。
function changeStyle($str) {
$arrStr=explode('_',$str);
foreach($arrStr as $key=>$value){
$arrStr[$key]=strtoupper(substr($value,0,1)).substr($value,1);
// $arrStr[$key]=Ucfirst($arrStr[$value]);
}
return implode('',$arrStr);
}
$str1 = "open_door";
$str2 = "make_by_id";
echo changeStyle ( $str1 );
echo changeStyle ( $str2 );
4. 要求写一段程序,实现以下数组$arr1转换成数组$arr2:
$arr1 = array (
'0' => array ('fid' => 1, 'tid' => 1, 'name' =>'Name1' ),
'1' => array ('fid' => 1, 'tid' => 2 , 'name' =>'Name2' ),
'2' => array ('fid' => 1, 'tid' => 5 , 'name' =>'Name3' ),
'3' => array ('fid' => 1, 'tid' => 7 , 'name' =>'Name4' ),
'4' => array ('fid' => 3, 'tid' => 9, 'name' =>'Name5' )
);
$arr2 = array (
'0' => array (
'0' => array ( 'tid' => 1, 'name' => 'Name1'),
'1' => array ( 'tid' => 2, 'name' => 'Name2'),
'2' => array ( 'tid' => 5, 'name' => 'Name3'),
'3' => array ( 'tid' => 7, 'name' => 'Name4')
),
'1' => array (
'0' => array ( 'tid' => 9, 'name' => 'Name5' ) // 内容来自技术世界www.js4j.com 技术爱好者//
)
);
$arr1 = array (
'0' => array ('fid' => 1, 'tid' => 1, 'name' =>'Name1' ),
'1' => array ('fid' => 1, 'tid' => 2 , 'name' =>'Name2' ),
'2' => array ('fid' => 1, 'tid' => 5 , 'name' =>'Name3' ),
'3' => array ('fid' => 1, 'tid' => 7 , 'name' =>'Name4' ),
'4' => array ('fid' => 3, 'tid' => 9, 'name' =>'Name5' )
);
function changeArrayStyle($arr){
foreach($arr as $key=>$value){
$result[$value['fid']][]=$value;
}
return array_values($result);
}
$arr2=changeArrayStyle($arr1);
echo "
"; <br>var_dump($arr2); <p><br><br>5. 请简述数据库设计的范式及应用。<br>一般第3范式就足以,用于表结构的优化,这样做既可以避免应用程序过于复杂同时也避免了SQL语句过于庞大所造成系统效率低下。 <br>ANSWER:<br>第一范式:若关系模式R的每一个属性是不可再分解的,再属于第一范式。<br>第二范式:若R属于第一范式,且所有的非码属性都完全函数依赖于码属性,则为第二范式。<br>第三范式:若R属于第二范式,且所有的非码属性没有一个是传递函数依赖于候选码,则属于第三范式。<br>6.一个表中的Id有多个记录,把所有这个id的记录查出来,并显示共有多少条记录数,用SQL语句及视图、存储过程分别实现。<br>存储过程: // 内容来自技术世界www.js4j.com 专业技术//</p> <p class="sycode"> DELIMITER // <br>create procedure proc_countNum(in columnId int,out rowsNo int) <br>begin <br>select count(*) into rowsNo from member where member_id=columnId; <br>end <br>call proc_countNum(1,@no); <br>select @no; </p> <p><br>视图:<br>create view v_countNum as select member_id,count(*) as countNum from member group by member_id<br>select countNum from v_countNum where member_id=1<br>7 表中有A B C三列,用SQL语句实现:当A列大于B列时选择A列否则选择B列,当B列大于C列时选择B列否则选择C列。</p> <p> </p> <p class="sycode"> select <br>case <br>when first_name>middle_name then <br>case when first_name>last_name then first_name <br>else last_name end <br>else <br>case when middle_name>last_name then middle_name else last_name <br>end <br>end as name <br>from member </p> <p><br>8请简述项目中优化sql语句执行效率的方法,从哪些方面,sql语句性能如何分析?<br>ANSWER: sql优化有鸟用,不如直接加索引。<br>9 如果模板是用smarty模板。怎样用section语句来显示一个名为$data的数组。比如:</p> <p> </p> <p class="sycode"> $data = array( <br>[0] => array( [id]=8 [name]=’name1′) <br>[1] => array( [id]=10 [name]=’name2′) <br>[2] => array( [id]=15 [name]=’name3′) <br>…… <br>) </p> <p><br>写出在模板页的代码? 若用foreach语句又要怎样显示呢?<br>占无答案.<br>10 写一个函数,能够遍历一个文件夹下的所有文件和子文件夹。(目录操作)</p> <p> </p> <p class="sycode"> $d = dir(dirname(__file__)); <br>//echo "Handle: " . $d->handle . "\n"; <br>//echo "Path: " . $d->path . "\n"; <br>while ( false !== ($entry = $d->read ()) ) { <br>echo $entry . "<br>"; <br>} <br>$d->close (); </p> <p><br><br>11 两张表 city表和province表。分别为城市与省份的关系表。<br>city:<br>id City Provinceid<br>1 广州 1<br>2 深圳 1<br>3 惠州 1<br>4 长沙 2<br>5 武汉 3<br>………. 广州 // 本文来自技术世界www.js4j.com 技术教程// <br>province:<br>id Province<br>1 广东<br>2 湖南<br>3 湖北<br>……….<br>(1) 写一条sql语句关系两个表,实现:显示城市的基本信息。?<br>(2) 显示字段:城市id ,城市名, 所属省份 。<br>如:<br>Id(城市id) Cityname(城市名) Privence(所属省份)<br>。。。。。。。。。<br>。。。。。。。。。<br>(2)如果要统计每个省份有多少个城市,请用group by 查询出来。?<br>显示字段:省份id ,省份名,包含多少个城市。<br>ANSWER:<br>1.select A.id,A.Cityname,B.Province from city A,province B where A.provinceid=B.id<br>2.select B.id,B.Province,count(*) as num from city A,province B where A.provinceid=B.id group by B.id</p> <br>12. 按照你的 经验 请简述软件工程进行软件开发的步骤。以下 工具 Rational Rose、PowerDesigner、Project、VSS或CVS、TestDirector使用过那种,有缺点是什么? <br> 公司 用dbdesigner及cvs,测试管理工具用的是Mantis <br>13. 请简述操作系统的线程与进程的区别。列举LINUX下面你使用过的软件? <br>14. 请使用伪语言结合数据结构冒泡排序法对以下一组数据进行排序 10 2 36 14 10 25 23 85 99 45。 // 本文来自技术世界www.js4j.com 技术教程// <p> </p> <p class="sycode"> function bubble_sort(& $arr){ <br>$number=count($arr); <br>for($i=0;$ifor($j=0;$j if($arr[$j]>$arr[$j+1]){ <br> $tmp=$arr[$j]; <br> $arr[$j]=$arr[$j+1]; <br> $arr[$j+1]=$tmp; <br> } <br>} <br>} <br>} <br>$str="10 2 36 14 10 25 23 85 99 45"; <br>$arr=explode(" ",$str); <br>bubble_sort($arr); <br>echo "</p><pre class="brush:php;toolbar:false">"; <br>var_dump($arr); <p> </p>

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