Home >Backend Development >PHP Tutorial >php生成rss文件求改进

php生成rss文件求改进

WBOY
WBOYOriginal
2016-06-23 14:27:59984browse

我写了一个php利用DOMDocument 组件生成rss文件的代码,但是感觉太过于臃肿,想封装成一个类但是一直没成功,特来请教
生成后rss大体是这样的





1123木头
1
http://www.xxx.com
id:1,user_name:,pass:123,real_name:木头




2456小木头
2
http://www.xxx.com
id:2,user_name:,pass:456,real_name:小木头





当然代码太过于冗余



$doc = new DOMDocument('1.0','utf-8');
$doc->formatOutput = true;


//创建标签
//创建rss标签
$rss = $doc->createElement('rss');
//创建channel下面的标签
$channel         = $doc->createElement('channel');
$ctitle         = $doc->createElement('title');
$clink             = $doc->createElement('link');
$cdescription     = $doc->createElement('description');






foreach ($arr as $key => $val) {
    //创建item标签
    $item             = $doc->createElement('item');
    //创建item下的子标签标签
    $user             = $doc->createElement('user');
    $ititle         = $doc->createElement('title');
    $ilink             = $doc->createElement('link');
    $idescription     = $doc->createElement('description');
    //创建user标签
    $user_id         = $doc->createElement('user_id');
    $user_name         = $doc->createElement('user_name');
    $user_pass         = $doc->createElement('user_pass');
    $real_name         = $doc->createElement('real_name');
    /*这里是需要数据库循环调用的地方*/
    //创建内容
    //创建item下面的标签的内容
    $c_ititle = $doc->createTextNode($val['user_id']);
    $c_ilink = $doc->createTextNode('http://www.xxx.com');
    $c_idescription = $doc->createTextNode('id:'.$val['user_id'].',user_name:'.$val['user_name'].',pass:'.$val['pass'].',real_name:'.$val['real_name']);
    //创建user下面的标签的内容
    $c_user_id        = $doc->createTextNode($val['user_id']);
    $c_user_name     = $doc->createTextNode($val['user_name']);
    $c_user_pass     = $doc->createTextNode($val['pass']);
    $c_real_name     = $doc->createTextNode($val['real_name']);
    //创建item属性值
    $a_id = $doc->createTextNode($val['user_id']);


    //创建属性
    $attributes = $doc->createAttribute('id');
    /*这里是需要数据库循环调用的地方*/
    //item一级标签的元素内容继承
    $ititle->appendChild($c_ititle);
    $ilink->appendChild($c_ilink);
    $idescription->appendChild($c_idescription);
    //user一级标签的元素内容继承
    $user_id->appendChild($c_user_id);
    $user_name->appendChild($c_user_name);
    $user_pass->appendChild($c_user_pass);
    $real_name->appendChild($c_real_name);
    /*这里是需要数据库循环调用的地方*/
    //继承
    $channel->appendChild($item);
    //item一级标签的标签继承
    $item->appendChild($user);
    $item->appendChild($ititle);
    $item->appendChild($ilink);
    $item->appendChild($idescription);
    //id=1
    $attributes->appendChild($a_id);
    //
    $item->appendChild($attributes);


    //item一级标签的标签继承
    $user->appendChild($user_id);
    $user->appendChild($user_name);
    $user->appendChild($user_pass);
    $user->appendChild($real_name);
}




//创建内容
//创建channel下面的标签的内容
$c_ctitle = $doc->createTextNode('测试rss');
$c_clink = $doc->createTextNode('http://www.xxx.com');
$c_cdescription = $doc->createTextNode('这是一个测试rss');
//创建rss版本属性值
$rss_attribute_c = $doc->createTextNode('2.0');


//创建rss版本属性
$rss_attribute = $doc->createAttribute('version');


//继承
//channel一级标签的元素内容继承
$ctitle->appendChild($c_ctitle);
$clink->appendChild($c_clink);
$cdescription->appendChild($c_cdescription);
//version="2.0"
$rss_attribute->appendChild($rss_attribute_c);




//channel一级标签的标签继承
$channel->appendChild($ctitle);
$channel->appendChild($clink);
$channel->appendChild($cdescription);








//创建根节点
$rss->appendChild($channel);
$rss->appendChild($rss_attribute);
$doc->appendChild($rss);


//保存xml文件
$doc->save('hello.xml');


function connect_sql(){
    $con = mysql_connect('localhost','root','123456') or die('mysql error :'.mysql_error());
    mysql_select_db('test');
    mysql_query('set names utf8');
}
function getall(){
    $sql = "SELECT * FROM test";
    $query = mysql_query($sql);
    $content = array();
    while($row = mysql_fetch_array($query)){
        $content[] = $row;
    }
    return $content;
}


请教各位大牛,怎样改装成一个class,我试了,一直不行


回复讨论(解决方案)

为什么要用 dom 呢?
直接字符串拼装不就可以的吗?如

$ar = array(  array(    'id' => 1,    'user' => array('user_id' => 1, 'user_name' => '', 'user_pass' => 123, 'real_name' => 'aa'),     'title' => 1,    'link' => 'http://www.xxx.com',    'description' => 'id:1,user_name:,pass:123,real_name:aa',  ),  array(    'id' => 2,    'user' => array('user_id' => 2, 'user_name' => '', 'user_pass' => 456, 'real_name' => 'bb'),     'title' => 2,    'link' => 'http://www.xxx.com',    'description' => 'id:1,user_name:,pass:456,real_name:bb',  ),);
<rss version="2.0"><item id="1"><id>1</id><user user_id="1" user_name="" user_pass="123" real_name="aa"><title>1</title><link>http://www.xxx.com</link><description>id:1,user_name:,pass:123,real_name:aa</description></item><item id="2"><id>2</id><user user_id="2" user_name="" user_pass="456" real_name="bb"><title>2</title><link>http://www.xxx.com</link><description>id:1,user_name:,pass:456,real_name:bb</description></item>

为什么要用 dom 呢?
直接字符串拼装不就可以的吗?如

$ar = array(  array(    'id' => 1,    'user' => array('user_id' => 1, 'user_name' => '', 'user_pass' => 123, 'real_name' => 'aa'),     'title' => 1,    'link' => 'http://www.xxx.com',    'description' => 'id:1,user_name:,pass:123,real_name:aa',  ),  array(    'id' => 2,    'user' => array('user_id' => 2, 'user_name' => '', 'user_pass' => 456, 'real_name' => 'bb'),     'title' => 2,    'link' => 'http://www.xxx.com',    'description' => 'id:1,user_name:,pass:456,real_name:bb',  ),);
<rss version="2.0"><item id="1"><id>1</id><user user_id="1" user_name="" user_pass="123" real_name="aa"><title>1</title><link>http://www.xxx.com</link><description>id:1,user_name:,pass:123,real_name:aa</description></item><item id="2"><id>2</id><user user_id="2" user_name="" user_pass="456" real_name="bb"><title>2</title><link>http://www.xxx.com</link><description>id:1,user_name:,pass:456,real_name:bb</description></item>

直接echo输出,然后fwrite写到一个xml文件中,这个好弄,只是我觉得既然php有自带的domdocument组件,那么是不是肯定有他的优点相比于直接拼凑生成文件,这个目前不清楚

Statement:
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn