php private
class Pc{
private $name;
function __construct($pcName){
$this->name=$pcName;
}
}
我想问为什么在方法中访问private的name需要用$this或者self,我直接用$name不行么?我把$this->name改为$name就有问题!不是private修饰的本类内部都可以访问么?求高手给个详细的解答,谢了
回复讨论(解决方案)
这与是否 private 无关
这是一个变量的作用域的问题
如写作
function __construct($pcName){
$name=$pcName;
}
那么出了 __construct 变量 $name 就不存在了
所以需要
function __construct($pcName){
$this->name=$pcName;
}
告诉 php name 是属性
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