Home >Backend Development >PHP Tutorial >PHP,变量里含有变量!

PHP,变量里含有变量!

WBOY
WBOYOriginal
2016-06-23 14:21:53987browse

php 变量

$mcontent 的内容是“ dear:{$user['username']}   你购买的商品:{$goods_name},订单号{$goods_no}已下单成功,由于此商品近期销售火爆,请及时付款!  ”


其中里面的也是变量,可以我 echo $mcontent;  输不出里的变量,请问大神要怎么做!!!

回复讨论(解决方案)

把程序段贴出来看看

字符串和变量之间要用.来连接
你试试这样
$mcontent = "dear:{".$user['username']."}   你购买的商品:{".$goods_name."},订单号{".$goods_no."}已下单成功,由于此商品近期销售火爆,请及时付款!";

内容是从数据库里读出来的,楼上的不行,你的方法,我也想过,直接在代码里还行,从数据库里读出来的不行!

		$query=new IQuery('msg_template');		$query->limit="1";		$query->where="id = 4";		$arra=$query->find();		$mtitle=$arra[0]['title'];		$mopen=$arra[0]['open'];		$mcontent=$arra[0]['content'];		$madmin_open=$arra[0]['admin_open'];		if($madmin_open==1){		$madmin_email=$arra[0]['admin_email'];		}     //$mcontent = "dear:{".$user['username']."}   你购买的商品:{".$goods_name."},订单号{".$goods_no."}已下单成功,由于此商品近期销售火爆,请及时付款!";	if($mopen==1){						$smtp  = new SendMail();		    $error = $smtp->getError();			$smtp->send($email,$mtitle,$mcontent,$madmin_email);	}

$content = "dear:{$user[username]}  你购买的商品:{$goods_name},订单号{$goods_no}已下单成功,由于此商品近期销售火爆,请及时付款!";
EOF;
echo $content;

楼上的也不行!!!!

楼上的也不行!!!!

你单独把这几个变量输出来看看什么情况


看不到源码啊...都不知道你的$mcontent 里的那些值是怎么来的~~~只能一个一个的打印啊.

//模拟从数据库中读出的数据$mcontent =<<< 'TXT'dear:{$user['username']}   你购买的商品:{$goods_name},订单号{$goods_no}已下单成功,由于此商品近期销售火爆,请及时付款!TXT;//涉及的变量需自行保证存在$user['username'] = 'body';$goods_name = 'xxx';$goods_no = '123';//方案一 不过有不少人恐惧 eval$mcontent = eval("return \"$mcontent\";");echo $mcontent;//方案二 动态创建函数,格式有点绕人$f = create_function('$user,$goods_name,$goods_no', "return \"$mcontent\";");$mcontent = $f($user, $goods_name, $goods_no);echo $mcontent;//或$f = create_function('$user,$goods_name,$goods_no', 'return "' . $mcontent . '";');$mcontent = $f($user, $goods_name, $goods_no);echo $mcontent;//方案三 模板变量替换,这是解释型模板引擎的做法$mcontent = preg_replace('/{\$[^}]+}/e', '$1', $mcontent);echo $mcontent;
均将得到:
dear:body
   你购买的商品:xxx,订单号123已下单成功,由于此商品近期销售火爆,请及时付款!

Statement:
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn