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关于php的number_format函数的问题.

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Jun 23, 2016 pm 02:14 PM

echo number_format(88899626759579787, 0, '', '');
为什么输出结果是88899626759579792 ?

回复讨论(解决方案)

我也是新手，问了下度娘，她说，格式出错了！
出自 http://www.w3school.com.cn/php/func_string_number_format.asp

因为你的环境应该32位，要表示你上述88899626759579787的数字，要用浮点型，而浮点型的精度是不没有办法保证的.

可以通过这个例子就知道了

echo PHP_INT_MAX; // php的整形能表示的最大整数var_dump(number_format(88899626759579700, 0, '', ''));

发帖的时候犹豫要不要写环境来着的.
开发环境是 win7 64bit, 生产环境是 centOS 64bit的.
还是同样错误.
有解决方法吗?
这个是从别的api娶过来的数字, 直接显示的话会显示科技计数法.
用的strval函数也不好用.
谢谢!

因为你的环境应该32位，要表示你上述88899626759579787的数字，要用浮点型，而浮点型的精度是不没有办法保证的.

可以通过这个例子就知道了

echo PHP_INT_MAX; // php的整形能表示的最大整数var_dump(number_format(88899626759579700, 0, '', ''));

另外. api返回来的是json数据. 我用json_decode(), 好像自动转换成数字类型.

还有php用的也是64位版本的..

有没有试过按 #1 说的改下看看

有没有试过按 #1 说的改下看看
16位数的是好使的.

越界了，php 的 long 类型无法表示那么大的正数

php 开发组织从未发行过 for win 的 64位版本

如果有条件的话，最好能升级到php5.4+，因为php在5.4的时候，对json_decode增加一个参数

5.4.0 The options parameter was added.

Bitmask of JSON decode options. Currently only JSON_BIGINT_AS_STRING is supported (default is to cast large integers as floats)

<?php$json = '12345678901234567890';var_dump(json_decode($json));var_dump(json_decode($json, false, 512, JSON_BIGINT_AS_STRING));?>以上例程会输出：float(1.2345678901235E+19)string(20) "12345678901234567890"

如果不能升级，建议首先将超过int整形长度的全数字文本首先加一个特殊标识，例如
{"a":"12345678901234567890"}
可以通过正则替换成
{"a":"__12345678901234567890"}
等json_decode完了以后，接着将__标识去掉

<?php$json = '12345678901234567890';var_dump(json_decode($json));var_dump(json_decode($json, false, 512, JSON_BIGINT_AS_STRING));?>以上例程会输出：float(1.2345678901235E+19)string(20) "12345678901234567890"

如果不能升级，建议首先将超过int整形长度的全数字文本首先加一个特殊标识，例如
{"a":"12345678901234567890"}
可以通过正则替换成
{"a":"__12345678901234567890"}
等json_decode完了以后，接着将__标识去掉
谢谢详细的回复.
已经解决了. 和如果不能升级的方法类似.
只是在开发环境取过来的数据是越界的, 在实际生产环境当中不会有越界的问题.
所以就字符串解析方法解决了.
再次感谢!
结贴!

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