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分享一行代码
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- 2016-06-23 14:05:39853browse
$arr = array(2=>'PHP','2'=>'mysql','2.5'=>'linux',2.5=>'apache');
var_dump($arr);
先仔细思考下，然后再运行下结果。
回复讨论(解决方案)
'2.5'不变
'2'转为2
2.5取整为2
后面赋值的覆盖前面的
结果略
思考同上，结果如下：
array(2) { [2]=> string(6) "apache" ["2.5"]=> string(5) "linux" }
长见识啦！长见识啦！
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