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分享一行代码

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2016-06-23 14:05:39858browse

$arr = array(2=>'PHP','2'=>'mysql','2.5'=>'linux',2.5=>'apache');  
var_dump($arr); 
先仔细思考下,然后再运行下结果。


回复讨论(解决方案)

'2.5'不变
'2'转为2
2.5取整为2
后面赋值的覆盖前面的

结果略

思考同上,结果如下:
array(2) { [2]=> string(6) "apache" ["2.5"]=> string(5) "linux" }

长见识啦!长见识啦!

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