Home >Backend Development >PHP Tutorial >一个关于文件上传的页面.遇到错误.求大神指导指导
一个关于文件上传的页面.遇到错误.求大神指导指导
- WBOYOriginal
- 2016-06-23 14:05:371000browse
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"><html xmlns="http://www.w3.org/1999/xhtml"><head><meta http-equiv="Content-Type" content="text/html; charset=gb2312" /><title>upload.</title><style type="text/css"><!--.STYLE2 { font-family: "宋体"; font-weight: bold;}--></style></head><body><style type="text/css"><!--tr,td{font-size:10px}--></style><center> <h1 class="STYLE2">upload your file</h1> <p> <table border="1" cellspacing="0" cellpadding="1" bordercolordark="#ffffff" bordercolorlight="#0000ff" width="400"> <form action="up_back.php" method="post" enctype="multipart/form-data"> <tr bgcolor="#ccccff"> <td>chose your file:</td> <td><input type="file" name="upfile" size=32 /></td> </tr> <tr> <td>describe:</td> <td><input type="text" name="describe" size="42" /></td> </tr> <tr> <td>owner:</td> <td><input type="text" name="owner" size="42" /></td> </tr> <tr> <td>submit:</td> <td><center><input type="submit" value="submit" /></center></td> </tr> </form> </table> </p></center> </body></html> 这个是用来前台的页面调用下面的php.
<?phpif (!$_POST["upfile"]&&$_FILES["upfile"]["name"]==""){ echo "no file<p>"; echo "click<a href=\"up_forward.html\">there</a>return!";}else { $filepath="upload/"; $name=$filepath.$_FILES["upload"]["name"]; while (file_exists($name)) { $temp=explode(".", $name); $name=$temp[0]."0".".".$temp[1]; } if(move_uploaded_file($_FILES["upfile"]["tmp_name"], $name)) { if ($_POST["owner"]) { $owner=$_POST["owner"]; } else { $owner="NULL"; } if ($_POST["describe"]) { $describe=$_POST["describe"]; } else { $describe="NONE"; } $time=date("y-m-d H:m:s"); $content=$_FILES["upload"]["name"]."||".$owner."||".$describe."||".$time."\n"; file_put_contents("record.dat", $content.FILE_APPEND); echo "name:".$_FILES["upfile"]["name"]; echo "<p>"; echo "is upload successfull.<p>"; echo "click<a href=\"up_forward.html\">there</a>return!"; } else { echo "upload error!<p>"; echo "fail!<p>"; echo "click<a href=\"index.php\">there</a>check!"; }}?> 问题就在于上传之后,提示文件上传成功,但是upload文件夹里面文件名是0的倍数,而且没有文件格式..这个是怎么回事呢?
提示的错误就是下面这些..
Notice: Undefined index: upfile in D:\phpnow\htdocs\b\up_back.php on line 2
Notice: Undefined index: upload in D:\phpnow\htdocs\b\up_back.php on line 10
Notice: Undefined offset: 1 in D:\phpnow\htdocs\b\up_back.php on line 14
Notice: Undefined index: upload in D:\phpnow\htdocs\b\up_back.php on line 35
name:10.jpg
回复讨论(解决方案)
这一行 $name=$filepath.$_FILES["upload"]["name"];
第一个文件上传的name="file" , 没有"upload" 啊.
move_uploaded_file($_FILES["upfile"]["tmp_name"], $name) 后面参数没有带路径
move_uploaded_file($_FILES["upfile"]["tmp_name"], $name) 后面参数没有带路径
他的$name=$filepath.$_FILES["upfile"]["name"];就是这个
1.
if (!$_POST["upfile"]&&$_FILES["upfile"]["name"]=="")
==>
if ($_FILES["upfile"]["name"]=="") //这样就能判断是否选择文件了
2.
$name=$filepath.$_FILES["upload"]["name"];
==》
$name=$filepath.$_FILES["upfile"]["name"];
3. 如果你的文件存在了。while循环不就成了死循环了吗，可以改为：
if(file_exists($name))
{
$temp=explode(".", $name);
$name=$temp[0]."0".".".$temp[1];
}
4. $content=$_FILES[" upfile"]["name"]."||".$owner."||".$describe."||".$time."\n";
1.
if (!$_POST["upfile"]&&$_FILES["upfile"]["name"]=="")
==>
if ($_FILES["upfile"]["name"]=="") //这样就能判断是否选择文件了
2.
$name=$filepath.$_FILES["upload"]["name"];
==》
$name=$filepath.$_……
谢谢你的帮助,根据这样修改后,确实完成了模块功能...万分感谢.
这一行 $name=$filepath.$_FILES["upload"]["name"];
第一个文件上传的name="file" , 没有"upload" 啊.
恩,确实这里有点毛病.谢谢你
1.
if (!$_POST["upfile"]&&$_FILES["upfile"]["name"]=="")
==>
if ($_FILES["upfile"]["name"]=="") //这样就能判断是否选择文件了
2.
$name=$filepath.$_FILES["upload"]["name"];
==》
$name=……
大神级人物 受教了