array(100-10, -50,200-20, 300-30, -30)求一个匹配到这个数组所有成员的正则
回复讨论(解决方案)
$arr = array('100-10', '-50','200-20', '300-30', '-30'); $b = array(); foreach ($arr as $value) { if(preg_match("/[\d-]+/", $value,$match)){ array_push($b, $match); } } var_dump($b);
$arr = array('100-10', '-50','200-20', '300-30', '-30'); $b = array(); foreach ($arr as $value) { if(preg_match("/[\d-]+/", $value,$match)){ array_push($b, $match); } } var_dump($b);
谢谢 但不是我想要的
我的需要 是这样的
$arr=array('200-30','lsflsdf','全场5折','50-10','100-30','-50','1000-100');
我需要把有'200-30'或'-30'这种类型的和其它类型的分开 分别赋给不同的变量
通过什么区分,- 符号么?
$arr = array('100-10', 'lsflsdf','全场5折','-50','200-20', '300-30', '-30','1000-100'); $a = array();//存放其他类型 $b = array();//存放'200-30'或'-30'这种类型 foreach ($arr as $value) { if(preg_match("/^[\d-]+/", $value,$match)){ array_push($b, $match); }else{ array_push($a, $value); } } var_dump($a,$b);//可以得到两个分开不同类型的结果啊

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