微信公众平台开发文本消息嵌入超链接失败，求助-PHP Tutorial-php.cn

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微信公众平台开发文本消息嵌入超链接失败，求助

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Jun 23, 2016 pm 01:57 PM

EmbedplatformdevelopHyperlink

$contentStr = "\n\n回复<a href="http://www.baidu.com/">百度</a>或回复“搜索” 了解详情\n其他文字";                                                                    $resultStr = sprintf($textTpl, $fromUsername, $toUsername, time(), $msgType, $contentStr);  /*$resultStr = "<xml>							<ToUserName><![CDATA[".$fromUsername."]]></ToUserName> 							<FromUserName><![CDATA[".$toUsername."]]></FromUserName> 							<CreateTime>".time()."</CreateTime>							<MsgType><![CDATA[text]]></MsgType>							<Content><![CDATA[文本\n\n回复<a href="http://www.baidu.com/">需要嵌入超链接的文本</a>或回复“搜索” 了解详情\n其他文字]]></Content>							</xml>";*/                echo $resultStr;

希望做过微信公众平台开发的指点下，网上说这么弄可以，但我的一直不成功，求解释

回复讨论(解决方案)

$contentStr = "\n\n回复<a href=\"http://www.baidu.com/\">百度</a>或回复“搜索” 了解详情\n其他文字";

$contentStr = "\n\n回复百度或回复“搜索” 了解详情\n其他文字";
难道这句话，你编辑器没有报错？

改成#1即可

或者
$contentStr = "\n\n回复百度或回复“搜索” 了解详情\n其他文字";

$contentStr = "\n\n回复<a href=\"http://www.baidu.com/\">百度</a>或回复“搜索” 了解详情\n其他文字";

问题解决了！这个“\”有什么用了？

这个用单引号是不行的，在iPhone上可以，但是在安卓手机显示异常。

$contentStr = "\n\n回复<a href=\"http://www.baidu.com/\">百度</a>或回复“搜索” 了解详情\n其他文字";

问题解决了！这个“\”有什么用了？

转义

这个用单引号是不行的，在iPhone上可以，但是在安卓手机显示异常。
是否是同一段代码？

这个用单引号是不行的，在iPhone上可以，但是在安卓手机显示异常。
是否是同一段代码？
是的，文本消息的超链有时在安卓和IOS上不一样

$contentStr = "\n\n回复<a href=\"http://www.baidu.com/\">百度</a>或回复“搜索” 了解详情\n其他文字";

问题解决了！这个“\”有什么用了？
这是转义。。。。
基础知识，建议LZ好好学习一下基础知识。

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