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请问怎么通过$a将张三和李四的id同时写入到表B的a_id

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2016-06-23 13:44:17967browse

表A
id       name
1        张三
2        李四

$a=‘张三,李四’
请问怎么通过$a将张三和李四的id同时写入到表B的a_id
即:
表B
id       a_id
1        1,2


回复讨论(解决方案)

假定 表B 的 id 为自增字段

insert into 表B (a_id) select group_concat(id) from A表

不是这样,我是说要通过变量$a

如果$a='张三';
那么a_id的值就写入1

insert into 表B (a_id) select group_concat(id) from A表 where find_in_set(name, '$a')


那如果是修改update怎么写??

update 表B set a_id=(select group_concat(id) from 表a where find_in_set(name, '$a'))
 

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