$name=$_POST['username'];
$pwd=$_POST['password'];
$con=mysql_connect("localhost","root","123456");
mysql_select_db("leelogin_db",$con);
if($name&&$pwd){
$sql="SELECT * FROM lee_tb WHERE username='$name'and password='$pwd'";
echo $sql;
$res=mysql_query($sql);
$rows=mysql_num_rows($res);
echo $rows;
if($rows){
echo "<script>alert('Login succeeded!');history.back()</script>";
}
}
上面是部分源代码 我加了两个echo来输出$sql 和$rows 但是每次都提示mysql_num_rows出错,报错如下:
SELECT * FROM lee_tb WHERE username='admin'and password='12456'
Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in F:\xampp\htdocs\phpstudy\login.php on line 18
在phpmyadmin中的对应数据表中有三个字段,自增的personID username password,但是就是查询不到结果集,求助求助~~~~
回复讨论(解决方案)
$res=mysql_query($sql) or die(mysql_error());
$res=mysql_query($sql,$con)
mysql_select_db("leelogin_db",$con);如果这个函数当中指定了连接标示符($con)那么在$res=mysql_query($sql);当中也要有连接标示符亦写作($res=mysql_query($sql,$con) )或者都不写连接标示符。
mysql_select_db("leelogin_db");
$rows=mysql_num_rows($res);
你记住,出现这种错误Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in F:\xampp\htdocs\phpstudy\login.php on line 18
基本上就是mysql_query($sql);错了,也就是你的sql语句错了!
username='admin'和and之间应该有个空格 如果字段存的是字符串 那么加引号! 如果是数字 不加引号!password=12456
SELECT * FROM lee_tb WHERE username='admin' and password='12456'

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