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很菜的前后台交互程序，用jq,ajax，json格式，
- WBOYOriginal
- 2016-06-23 13:43:26884browse
前台输意一个数字，后台处理，比如加2，再返回前台，求教。请别嘲笑。
回复讨论(解决方案)
html代码部分：
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"><html xmlns="http://www.w3.org/1999/xhtml"><head><meta http-equiv="Content-Type" content="text/html; charset=utf-8" /><title>无标题文档</title><script src="http://cloud.xing-xing.com/jquery.js"></script><script type="text/javascript" language="javascript">$(function(){ $.get('handle.php',{num:1},function(data){ $("div").html(data);//在div里面输出3 }) })</script></head><body><div></div></body></html> handle.php代码部分：
<?phpecho $_GET['num']+2;?>
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