phpexcel 导出图片
我在网上看了资料 都是导出一张图片,我想导出每行第一列是一个图片,如何实现,下边是一个导出的方法,我应该怎么加入哪?其他的数据都导出来了,就图片出不来,图片的路径信息保存到了$data二维数组下 。注:类库已导入。坐等。。。
//写入excelfunction getExcel($fileName,$headArr,$data){ if(empty($data) || !is_array($data)){ die("data must be a array"); } if(empty($fileName)){ exit; } $date = date("Y_m_d h:i:s",time()); $fileName .= "_{$date}.xlsx"; //创建新的PHPExcel对象 $objPHPExcel = new PHPExcel(); $objProps = $objPHPExcel->getProperties(); //设置表头 $key = ord("A"); foreach($headArr as $v){ $colum = chr($key); $objPHPExcel->setActiveSheetIndex(0) ->setCellValue($colum.'1', $v); $key += 1; } //表数据 $column = 2; $objActSheet = $objPHPExcel->getActiveSheet(); foreach($data as $key => $rows){ //行写入 $span = ord("A"); foreach($rows as $keyName=>$value){// 列写入 $j = chr($span); //我想在此处加入图片的code但是不成功,应该怎么写,请提示下 // $objDrawing = new PHPExcel_Worksheet_Drawing(); // $objDrawing->setName(‘test’); // $objDrawing->setDescription(‘test’); // $objDrawing->setPath($data['imgurl']); // $objDrawing->setHeight(36); // $objDrawing->setCoordinates(''); 这里应该怎么写?? // $objDrawing->setWorksheet($objActSheet); $objActSheet->setCellValue($j.$column, $value); $span++; } $column++; } //重命名表 $objPHPExcel->getActiveSheet()->setTitle('记录'); $fileName = iconv("utf-8", "gb2312", $fileName); $objWriter = PHPExcel_IOFactory::createWriter($objPHPExcel, 'Excel2007'); $objWriter->save($fileName); //脚本方式运行,保存在当前目录 exit;}
回复讨论(解决方案)
1、被你注释掉的导出图片的代码中,你使用了全角的引号,应改为半角的
2、$objDrawing->setCoordinates('这里是单元格标识');
1、被你注释掉的导出图片的代码中,你使用了全角的引号,应改为半角的
2、$objDrawing->setCoordinates('这里是单元格标识');
1.全角是我发帖时贴过来的 = =
2.$objDrawing->setCoordinates('这里是单元格标识'); 这个标示在那个循环里应该怎么赋值,我想放在第一列里。

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