这些缓存php文件都放在cache目录下如:
a.php
b.php
c.php
这些php文件中的内容都是一些缓存数据,我存储的时候都是以数组形式写入:
如:a.php文件
$aArr=array (
'aaa' => '111',
'bbb' => '222',
'ccc' => '3333',
);
?>
如:b.php文件
$bArr=array (
'aaa' => '111',
'bbb' => '222',
'ccc' => '3333',
);
?>
如:c.php文件
$cArr=array (
'aaa' => '111',
'bbb' => '222',
'ccc' => '3333',
);
?>
现在想把这个目录下的所有php文件写到一个php中
下面是我写的代码,但是写入文件后,发现把以后文件php标识也写进来了,把我把缓存文件的数组格式也转义
大师怎么怎么修改一下,
//创建缓存目录$dir="cache";$fileDir=@opendir($dir); if(!$fileDir){ echo '打开目录失败'; exit;}while(false!==($file=@readdir($fileDir))){ //跳过本目录以及上级目录 if ('.' === $file || '..' === $file) continue; //获取文件后缀 $filetype=substr($file,strripos($file,".")+1); //文件路径 $filepath=$dir.'/'.$file; //判断是不是php文件,并判断是否存在 if($filetype=='php' && is_file($filepath)){ $handle = fopen($filepath,"r"); $contents.= fread($handle,filesize($filepath)); fclose($handle); } }write('data.php',"<?php\r\n\$listDB=".var_export($contents,true).";\r\n?>");
回复讨论(解决方案)
过滤PHP标识可以这样
第18行改为:
$contents.= rtrim(ltrim(fread($handle,filesize($v)),'<?php'),'?>');
转义是因为var_export这个函数吧。
过滤掉 是不必要的,有时反而会出错(假如数据中就有呢)
$dir = "cache";$out = 'data.php';file_put_contents($out);foreach(glob("$dir/*.php") as $fn) { file_put_contents($out, file_get_contents($fn), FILE_APPEND);}
过滤掉 是不必要的,有时反而会出错(假如数据中就有呢)
$dir = "cache";$out = 'data.php';file_put_contents($out);foreach(glob("$dir/*.php") as $fn) { file_put_contents($out, file_get_contents($fn), FILE_APPEND);}
这样写代码好像比我那样写效率要高,学习了!!
但是如果不删除 php 标识,生成的文件就成这样了?该如何改进下??
<?php$aDB=array ( 'aaa' => '111', 'bbb' => '222', 'ccc' => '333',);?><?php$bDB=array ( 'aaa' => '111', 'bbb' => '222', 'ccc' => '333',);?><?php$cDB=array ( 'aaa' => '111', 'bbb' => '222', 'ccc' => '333',);?><?php$dDB=array ( 'aaa' => '111', 'bbb' => '222', 'ccc' => '333',);?>
//获取文件后缀 并确定是否为php后缀if(substr($file, -4)== '.php'){ .........}
我觉得定义一个类 然后抓取数据的就好了,其实没多复杂
str_replace 先把PHP标识替换为空,之后就简单了

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