preg_replace怎么将src="/n1/images替换成src="images
src="/n1/images 中的n1 可能是其他字符，比如说m2或者py等。
不懂正则替换，请指点。
回复讨论(解决方案)
$s =<<< TXT<img src="/static/imghwm/default1.png" data-src="/n1/images" class="lazy" alt="preg_replace怎么将src="/n1/images替换成src="images" ><img src="/static/imghwm/default1.png" data-src="/x2/images1" class="lazy" alt="preg_replace怎么将src="/n1/images替换成src="images" ><img src="/static/imghwm/default1.png" data-src="/a/b/images2" class="lazy" alt="preg_replace怎么将src="/n1/images替换成src="images" >TXT;echo preg_replace('#(?<=src=").*/([^"]+)#', '$1', $s); <img src="/static/imghwm/default1.png" data-src="images" class="lazy" alt="preg_replace怎么将src="/n1/images替换成src="images" ><img src="/static/imghwm/default1.png" data-src="images1" class="lazy" alt="preg_replace怎么将src="/n1/images替换成src="images" ><img src="/static/imghwm/default1.png" data-src="images2" class="lazy" alt="preg_replace怎么将src="/n1/images替换成src="images" >
$s =<<< TXT<img src="/static/imghwm/default1.png" data-src="/n1/images" class="lazy" alt="preg_replace怎么将src="/n1/images替换成src="images" ><img src="/static/imghwm/default1.png" data-src="/x2/images1" class="lazy" alt="preg_replace怎么将src="/n1/images替换成src="images" ><img src="/static/imghwm/default1.png" data-src="/a/b/images2" class="lazy" alt="preg_replace怎么将src="/n1/images替换成src="images" >TXT;echo preg_replace('#(?<=src=").*/([^"]+)#', '$1', $s); <img src="/static/imghwm/default1.png" data-src="images" class="lazy" alt="preg_replace怎么将src="/n1/images替换成src="images" ><img src="/static/imghwm/default1.png" data-src="images1" class="lazy" alt="preg_replace怎么将src="/n1/images替换成src="images" ><img src="/static/imghwm/default1.png" data-src="images2" class="lazy" alt="preg_replace怎么将src="/n1/images替换成src="images" >
谢谢版主，但如果是
怎么办？ 替换成 类似的应该怎么做，
你的需求不明确，前后矛盾，到底保留文件本身，还是保留文件名以及他的父级目录。
你的需求不明确，前后矛盾，到底保留文件本身，还是保留文件名以及他的父级目录。
其实就是将
替换成 意思是将 images前面的目录删除
$str="src='/n1sss/images'“;
$zz="/src='\/.*\/(.*?)'/";
echo preg_replace($zz,'$1',$str);
$str="src='/n1sss/images'“;
$zz="/src='\/.*\/(.*?)'/";
echo preg_replace($zz,'$1',$str);
这个 $zz="/src='\/.*\/(.*?)'/"; 在PHP里面就有错误
<?php$s =<<< TXT<img src="/static/imghwm/default1.png" data-src="/a/b/images/hehehahha" class="lazy" alt="preg_replace怎么将src="/n1/images替换成src="images" >TXT;$pattern="/\/.*\/(.*?)\/(.*?)/";echo preg_replace($pattern, '$1/$2', $s);?>
<?php$s =<<< TXT<img src="/static/imghwm/default1.png" data-src="/a/b/images/hehehahha" class="lazy" alt="preg_replace怎么将src="/n1/images替换成src="images" >TXT;$pattern="/\/.*\/(.*?)\/(.*?)/";echo preg_replace($pattern, '$1/$2', $s);?>
谢谢版主的回答，可能我的问题说的不是很明确，
利用preg_replace怎么将images前面的目录删除掉
将
或者
<?php$s =<<< TXT<img src="/static/imghwm/default1.png" data-src="/a/b/images/hehehahha" class="lazy" alt="preg_replace怎么将src="/n1/images替换成src="images" >TXT;$pattern="/\/.*\/(.*?)\/(.*?)/";echo preg_replace($pattern, '$1/$2', $s);?>
还请再帮帮忙
$s =<<< TXT<img src="/static/imghwm/default1.png" data-src="/n1/images" class="lazy" alt="preg_replace怎么将src="/n1/images替换成src="images" ><img src="/static/imghwm/default1.png" data-src="/x2/images1" class="lazy" alt="preg_replace怎么将src="/n1/images替换成src="images" ><img src="/static/imghwm/default1.png" data-src="/a/b/images2" class="lazy" alt="preg_replace怎么将src="/n1/images替换成src="images" ><img src="/static/imghwm/default1.png" data-src="/a/b/images2/hehehahha" class="lazy" alt="preg_replace怎么将src="/n1/images替换成src="images" >TXT;$n = 0; //只留文件名echo preg_replace("#(?<=src=['\"]).*/((?:.*/){{$n}}[^'\"]+)#", '$1', $s);$n = 1; //保留一级目录echo preg_replace("#(?<=src=['\"]).*/((?:.*/){{$n}}[^'\"]+)#", '$1', $s);$n = 2; //保留二级目录echo preg_replace("#(?<=src=['\"]).*/((?:.*/){{$n}}[^'\"]+)#", '$1', $s); <img src="/static/imghwm/default1.png" data-src="images" class="lazy" alt="preg_replace怎么将src="/n1/images替换成src="images" ><img src="/static/imghwm/default1.png" data-src="images1" class="lazy" alt="preg_replace怎么将src="/n1/images替换成src="images" ><img src="/static/imghwm/default1.png" data-src="images2" class="lazy" alt="preg_replace怎么将src="/n1/images替换成src="images" >
$s =<<< TXT<img src="/static/imghwm/default1.png" data-src="/n1/images" class="lazy" alt="preg_replace怎么将src="/n1/images替换成src="images" ><img src="/static/imghwm/default1.png" data-src="/x2/images1" class="lazy" alt="preg_replace怎么将src="/n1/images替换成src="images" ><img src="/static/imghwm/default1.png" data-src="/a/b/images2" class="lazy" alt="preg_replace怎么将src="/n1/images替换成src="images" ><img src="/static/imghwm/default1.png" data-src="/a/b/images2/hehehahha" class="lazy" alt="preg_replace怎么将src="/n1/images替换成src="images" >TXT;$n = 0; //只留文件名echo preg_replace("#(?<=src=['\"]).*/((?:.*/){{$n}}[^'\"]+)#", '$1', $s);$n = 1; //保留一级目录echo preg_replace("#(?<=src=['\"]).*/((?:.*/){{$n}}[^'\"]+)#", '$1', $s);$n = 2; //保留二级目录echo preg_replace("#(?<=src=['\"]).*/((?:.*/){{$n}}[^'\"]+)#", '$1', $s); <img src="/static/imghwm/default1.png" data-src="images" class="lazy" alt="preg_replace怎么将src="/n1/images替换成src="images" ><img src="/static/imghwm/default1.png" data-src="images1" class="lazy" alt="preg_replace怎么将src="/n1/images替换成src="images" ><img src="/static/imghwm/default1.png" data-src="images2" class="lazy" alt="preg_replace怎么将src="/n1/images替换成src="images" >
$s =<<< TXT<img src="/static/imghwm/default1.png" data-src="/n1/images" class="lazy" alt="preg_replace怎么将src="/n1/images替换成src="images" ><img src="/static/imghwm/default1.png" data-src="/x2/images1" class="lazy" alt="preg_replace怎么将src="/n1/images替换成src="images" ><img src="/static/imghwm/default1.png" data-src="/a/b/images2" class="lazy" alt="preg_replace怎么将src="/n1/images替换成src="images" ><img src="/static/imghwm/default1.png" data-src="/a/b/images2/hehehahha" class="lazy" alt="preg_replace怎么将src="/n1/images替换成src="images" >TXT;$n = 0; //只留文件名echo preg_replace("#(?<=src=['\"]).*/((?:.*/){{$n}}[^'\"]+)#", '$1', $s);$n = 1; //保留一级目录echo preg_replace("#(?<=src=['\"]).*/((?:.*/){{$n}}[^'\"]+)#", '$1', $s);$n = 2; //保留二级目录echo preg_replace("#(?<=src=['\"]).*/((?:.*/){{$n}}[^'\"]+)#", '$1', $s); <img src="/static/imghwm/default1.png" data-src="images" class="lazy" alt="preg_replace怎么将src="/n1/images替换成src="images" ><img src="/static/imghwm/default1.png" data-src="images1" class="lazy" alt="preg_replace怎么将src="/n1/images替换成src="images" ><img src="/static/imghwm/default1.png" data-src="images2" class="lazy" alt="preg_replace怎么将src="/n1/images替换成src="images" >
$s =<<< TXT<img src="/static/imghwm/default1.png" data-src="/n1/images" class="lazy" alt="preg_replace怎么将src="/n1/images替换成src="images" ><img src="/static/imghwm/default1.png" data-src="/x2/images1" class="lazy" alt="preg_replace怎么将src="/n1/images替换成src="images" ><img src="/static/imghwm/default1.png" data-src="/a/b/images2" class="lazy" alt="preg_replace怎么将src="/n1/images替换成src="images" ><img src="/static/imghwm/default1.png" data-src="/a/b/images2/hehehahha" class="lazy" alt="preg_replace怎么将src="/n1/images替换成src="images" >TXT;$n = 0; //只留文件名echo preg_replace("#(?<=src=['\"]).*/((?:.*/){{$n}}[^'\"]+)#", '$1', $s);$n = 1; //保留一级目录echo preg_replace("#(?<=src=['\"]).*/((?:.*/){{$n}}[^'\"]+)#", '$1', $s);$n = 2; //保留二级目录echo preg_replace("#(?<=src=['\"]).*/((?:.*/){{$n}}[^'\"]+)#", '$1', $s); <img src="/static/imghwm/default1.png" data-src="images" class="lazy" alt="preg_replace怎么将src="/n1/images替换成src="images" ><img src="/static/imghwm/default1.png" data-src="images1" class="lazy" alt="preg_replace怎么将src="/n1/images替换成src="images" ><img src="/static/imghwm/default1.png" data-src="images2" class="lazy" alt="preg_replace怎么将src="/n1/images替换成src="images" >
谢谢版主的回答，我有一个文件夹images，我就想保留images文件夹以及后面的目录，images后面的目录有几级是未知的。还请版主帮个忙
$str="src='/n1sss/images'“;
$zz="/src='\/.*\/(.*?)'/";
echo preg_replace($zz,'$1',$str);
我都运行过的没问题，才发出来的啊
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