菜鸟求教: 怎么样才可以把从数据库取出来的值转换成这样的json请大神指教 谢谢
回复讨论(解决方案)
把结果集json_encode 注意编码 中文 \n \t等问题
把结果集json_encode 注意编码 中文 \n \t等问题
下面是我写的代码但是输出的结果不是我想要的那种
不需要urldecode,之间json_encode就可以了
不需要urldecode,之间json_encode就可以了
urldecode是为了转换成中文字符
现在我那样写输出的结果形式值这样的
$index = "select roomName as name, note as content, createtime as date, rooMaxusers as num, roomImageUrl as src from tc_room";$info = mysql_query($index);while($result = mysql_fetch_row($info)) { $aa['metingroom'][] = $result; $aa['room'][] = $result;}echo json_encode($aa);
把结果集json_encode 注意编码 中文 \n \t等问题
下面是我写的代码但是输出的结果不是我想要的那种
function jsonformat($str) { return preg_replace('/[\n\r\t]/','',urldecode(json_encode(url_encode($str)))); } function url_encode($str) { if(is_array($str)) { foreach($str as $key=>$value) { $str[urlencode($key)] = url_encode($value); } } else { $str = urlencode($str); } return $str; } $index = " xxx";$info = myslq_query($index);while($result = mysql_fetch_array($info)){ $res[]=$result;}jsonformat($res);
同一个数据还分 meetingroom和room。。。 好吧 while里面的参考老大的。。
把结果集json_encode 注意编码 中文 \n \t等问题
下面是我写的代码但是输出的结果不是我想要的那种
[code=php]
function jsonformat($str) {
return preg_replace('/[\n\r\t]/','',urldecode(json_encode(url_encode($str))));
}
function url_encode($str) {
if(is_array($str)) {
foreach($str as $key=>$value) {
$str[urlencode($key)] = url_encode($value);
}
} else {
$str = urlencode($str);
}
return $str;
}
$index = " xxx";
$info = myslq_query($index);
while($result = mysql_fetch_array($info)){
$res[]=$result;
}
jsonformat($res);
这个根本输出不了数据的
同一个数据还分 meetingroom和room。。。 好吧 while里面的参考老大的。。
大神这个是什么意思啊 不懂
同一个数据还分 meetingroom和room。。。 好吧 while里面的参考老大的。。
大神这个是什么意思啊 不懂
这个只return了
echo一下就行了。。
这段代码就是把你数组等格式化输出json格式的
同一个数据还分 meetingroom和room。。。 好吧 while里面的参考老大的。。
大神这个是什么意思啊 不懂
这个只return了
echo一下就行了。。
这段代码就是把你数组等格式化输出json格式的
为什么用这种输出来貌似有重复的呢
同一个数据还分 meetingroom和room。。。 好吧 while里面的参考老大的。。
大神这个是什么意思啊 不懂
这个只return了
echo一下就行了。。
这段代码就是把你数组等格式化输出json格式的
为什么用这种输出来貌似有重复的呢
while 那里用mysql_fetch_row 或者 mysql_fetch_array($info,MYSQL_ASSOC)后面带上参数
是我大意了

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