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php截取字符串问题
- WBOYOriginal
- 2016-06-20 12:46:14953browse
"UID": 0, "RID": 0, "Name": "张三", "Sex": "女", "Age": 30,"mobile": "10000", "Job": "公司职员","remark": "很好",
"ImgList": "a.jpg,b.jpg", "Time": 1000000 怎么实现把他变成数组 的形式 以：前面为键名后面为键值 调用时可以直接
回复讨论(解决方案)
$str = '"UID": 0, "RID": 0, "Name": "张三", "Sex": "女", "Age": 30,"mobile": "10000", "Job": "公司职员","remark": "很好", "ImgList": "a.jpg,b.jpg", "Time": 1000000';$str = '{'.$str.'}';$data = json_decode($str, true);echo $data['Name'].'<br>';print_r($data);
"UID": 0, "RID": 0, "Name": "张三", "Sex": "女", "Age": 30,"mobile": "10000", "Job": "公司职员","remark": "很好",
"ImgList": "a.jpg,b.jpg", "Time": 1000000 怎么实现把他变成数组 的形式 以：前面为键名后面为键值 调用时可以直接
谢谢大神！真是太及时了！！！万分感谢！！
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