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用ajax怎么提交插入数据库？
- WBOYOriginal
- 2016-06-20 12:35:34844browse
我昨天只是试着用ajax做了一个验证用户名的效果 用的是数据的查询 但是我做了一个提交插入数据库的页面 我还是用的查询的那一套办法做的 试了一下不成功 插不到数据库里面 我这种做法是不是不对呢
这是数据库
这是前端页面
<!DOCTYPE html><html><head> <meta charset="utf-8"> <title></title> <script type="text/javascript"> function ajax(url,funsucc){ var oAjax=new XMLHttpRequest(); oAjax.open('GET',url,true); oAjax.send(); oAjax.onreadystatechange=function(){ if(oAjax.readyState==4){ if(oAjax.status==200){ funsucc(oAjax.responseText); } }}} </script> <script type="text/javascript"> window.onload=function(){ var oTxt=document.getElementById('txt1'); var oBtn=document.getElementById('btn1'); oBtn.onclick=function(){ ajax("ajaxinsert.php?id="+oTxt.value); //不知道这里怎么写 只写了一个url } } </script></head><body><form> <input type="text" id="txt1"> <button type="submit" id="btn1">提交</button></form></body></html> 后台(ajaxinsert.php)
$pdo=new PDO("mysql:host=localhost;dbname=t1","root","");
$id=$_GET["id"];
$stmt=$pdo->prepare("insert into ajax(txt)values(:txt)");
$stmt->execute(array($id));
?>
回复讨论(解决方案)
$stmt=$pdo->prepare("insert into ajax (txt) values (:txt)");
$stmt->execute(array(‘:txt' =>$id));
或
$stmt=$pdo->prepare("insert into ajax (txt) values (?)");
$stmt->execute(array($id));
改成这样
<?php$pdo=new PDO("mysql:host=localhost;dbname=t1","root","");$id=$_GET["id"];$stmt=$pdo->prepare("insert into ajax(txt) values(?)");$stmt->execute(array($id));?> Statement：
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