求一个htaccess规则。请高手帮写一下。谢谢
求一个htaccess规则
/tel/index.php?id=4 转换成下面这样
/4__tel/index.php
------解决方案--------------------
RewriteEngine on
RewriteCond %{REQUEST_FILENAME} !-d
RewriteCond %{REQUEST_FILENAME} !-f
RewriteRule ^.*/([0-9]+)__tel/index.php /tel/index.php?id=$1 [QSA,L]
------解决方案--------------------
([0-9]+) ,[]表示一个范围 0-9的任意一个数字!
------解决方案--------------------
apache 配置文件中的 rewrite_module 开了吗?
------解决方案--------------------
- PHP code
方法1. RewriteEngine on RewriteCond %{REQUEST_FILENAME} !-d RewriteCond %{REQUEST_FILENAME} !-f RewriteRule ^(.*)$ index.php/$1 [QSA,L] RewriteRule ^(.*)/([0-9]+)__tel/index.php $1/tel/index.php?id=$2 [QSA,L] 方法2. RewriteEngine on RewriteCond %{REQUEST_FILENAME} !-d RewriteCond %{REQUEST_FILENAME} !-f RewriteBase /tel/ RewriteRule ([0-9]+)__tel/index.php index.php?id=$1 [QSA,L] <div class="clear"> </div>

index.html代表网页的首页文件,是网站的默认页面。当用户访问一个网站时,通常会首先加载index.html页面。HTML(HypertextMarkupLanguage)是一种用于创建网页的标记语言,index.html也是一种HTML文件。它包含网页的结构和内容,以及用于格式化和布局的标签和元素。下面是一个示例的index.html代码:<

php把负数转为正整数的方法:1、使用abs()函数将负数转为正数,使用intval()函数对正数取整,转为正整数,语法“intval(abs($number))”;2、利用“~”位运算符将负数取反加一,语法“~$number + 1”。

request的中文意思为“请求”,是php中的一个全局变量,是一个包含了“$_POST”、“$_GET”和“$_COOKIE”的数组。“$_REQUEST”变量可以获取POST或GET方式提交的数据、COOKIE信息。

php除以100保留两位小数的方法:1、利用“/”运算符进行除法运算,语法“数值 / 100”;2、使用“number_format(除法结果, 2)”或“sprintf("%.2f",除法结果)”语句进行四舍五入的处理值,并保留两位小数。

判断方法:1、使用“strtotime("年-月-日")”语句将给定的年月日转换为时间戳格式;2、用“date("z",时间戳)+1”语句计算指定时间戳是一年的第几天。date()返回的天数是从0开始计算的,因此真实天数需要在此基础上加1。

在php中,可以使用substr()函数来读取字符串后几个字符,只需要将该函数的第二个参数设置为负值,第三个参数省略即可;语法为“substr(字符串,-n)”,表示读取从字符串结尾处向前数第n个字符开始,直到字符串结尾的全部字符。

php判断有没有小数点的方法:1、使用“strpos(数字字符串,'.')”语法,如果返回小数点在字符串中第一次出现的位置,则有小数点;2、使用“strrpos(数字字符串,'.')”语句,如果返回小数点在字符串中最后一次出现的位置,则有。

查找方法:1、用strpos(),语法“strpos("字符串值","查找子串")+1”;2、用stripos(),语法“strpos("字符串值","查找子串")+1”。因为字符串是从0开始计数的,因此两个函数获取的位置需要进行加1处理。


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