string(8) "2_334" [2]=> string(4) "1" [3]=> string(4) "2"   [4]=> string(9) &"/> string(8) "2_334" [2]=> string(4) "1" [3]=> string(4) "2"   [4]=> string(9) &">

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php 数组比较取值,该怎么解决

WBOY
WBOYOriginal
2016-06-13 13:44:26653browse

php 数组比较取值
{ [0]=> string(9) "1_29" [1]=> string(8) "2_334" [2]=> string(4) "1" [3]=> string(4) "2"
  [4]=> string(9) "1_30" [5]=> string(8) "5_334" [6]=> string(4) "6" [7]=> string(4) "10" } 
 
用‘-'分开的前面的值在数据里跟没有'-'的值相同就不取这条数据
比如1_29因为数据里有1跟[2]=> string(4) "1"相同就不取
最后结果只有有‘-’且没有重复的
{[5]=> string(8) "5_334" }


------解决方案--------------------

$a=array("1_29","2_334","1","2","1_30","5_334","6","10");
var_dump($a);

$keys=array();
$result=array();
foreach($a as $val){
if(is_numeric($val))
$keys[]=$val;
}
foreach($a as $val){
if(!is_numeric($val)){
$tmp=explode("_",$val);
if(count($tmp)==2&&!in_array($tmp[0],$keys))
$result[]=$val;
}
}
var_dump($result);
?>

输出:

array(8) {
[0]=>
string(4) "1_29"
[1]=>
string(5) "2_334"
[2]=>
string(1) "1"
[3]=>
string(1) "2"
[4]=>
string(4) "1_30"
[5]=>
string(5) "5_334"
[6]=>
string(1) "6"
[7]=>
string(2) "10"
}
array(1) {
[0]=>
string(5) "5_334"
}

------解决方案--------------------
很土的代码,不过结果是你要的.

PHP code

$Array = array ('1_29', '2_334', '1', '2', '1_30', '5_334', '6', '10' );
$ReferArray = array ();
$FixArray = array ();
$MyArray = array ();
foreach ( $Array as $Value ) {
    if (strpos ( $Value, '_' ) == false) {
        $ReferArray [] = $Value;
    } else {
        $FixArray [] = substr ( $Value, 0, 1 );
        $MyArray [] = $Value;
    }
}

$FixArray = array_diff ( $FixArray, $ReferArray );
foreach ( $FixArray as $Key => $Value ) {
    echo $MyArray [$Key];
} <div class="clear">
                 
              
              
        
            </div>
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