Home >Backend Development >PHP Tutorial > 为什么javascript的报错没什么用解决方法
为什么javascript的报错没什么用解决方法
- WBOYOriginal
- 2016-06-13 13:33:32812browse
为什么javascript的报错没什么用
要崩溃了，为什么javascript的报错没什么用？
include("conn.php");
if(isset($_POST["submit"]))
{
$sql="INSERT INTO message (id,user,title,content,lastdate) " .
"values ('','$_POST[user]','$_POST[title]','$_POST[content]',now())";
//echo $sql;
$result = mysql_query($sql,$conn)or die(mysql_error());
}
?>
------解决方案--------------------
if (document.myform.user.value=="")
Statement：
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Previous article： phpMyAdmin - 异常“缺少 mysqli 扩展”() Next article： 哪里有比较好的php项目源代码？该如何解决