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从数据库读取二进制图片显示有关问题

WBOY
WBOYOriginal
2016-06-13 13:28:54856browse

从数据库读取二进制图片显示问题
$conn=mssql_connect("192.168.1.70","XXX","123") or die("数据库打开出错");
mssql_select_db("XXX");
mssql_query("set names utf8");

$sql = "SELECT top 1 * FROM sync_info_BlogPic";

$result2=mssql_query($sql);
header("Content-Type: image/jpg");
$row2=mssql_fetch_object($result2);

echo $row2->BlogPic_Content;



error:Image corrupt or truncated



------解决方案--------------------
错误:图像损坏或截断

你是用什么类型字段保存图片的?
------解决方案--------------------
怎么读不重要,怎么存的?
------解决方案--------------------
肯定是入库出问题了, 别想了.
------解决方案--------------------
php 提供给 mssql 的缓冲区可能偏小了
------解决方案--------------------
php.ini

[MSSQL]
; Valid range 0 - 2147483647. Default = 4096.
;mssql.textlimit = 4096

; Valid range 0 - 2147483647. Default = 4096.
;mssql.textsize = 4096

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