Home >Backend Development >PHP Tutorial > mysql怎么打印数组中最新的购买的产品信息

mysql怎么打印数组中最新的购买的产品信息

WBOY
WBOYOriginal
2016-06-13 13:27:27883browse

mysql如何打印数组中最新的购买的产品信息
有一个book表(stitle是产品名称,一个ID可以购买多个book,如ID为1的用户购买 a,b 2个产品)

SQL code
<!--

Code highlighting produced by Actipro CodeHighlighter (freeware)
http://www.CodeHighlighter.com/

-->
字段  id      stitle    time

      1       a,b,     2011-01-01

      2       c,d,     2011-01-02

      3       a,       2011-01-03
 
      4       b,e,     2011-01-04

      5       c,       2011-01-05



现在请教如何打印最新的前5条购买产品的名称,显示的顺序应该是:


c,b,e,a,d







------解决方案--------------------
SQL code
SELECT LEFT(GROUP_CONCAT(stitle),10) FROM (SELECT TRIM(',' FROM stitle) AS stitle FROM `book` ORDER BY time DESC LIMIT 5)a
<br><font color="#e78608">------解决方案--------------------</font><br>我觉得逆序搜5条就好了<br><br>然后纳入数组,,因为重复不足5项,重复这个过程
<br><font color="#e78608">------解决方案--------------------</font><br>其实他必有一个产品目录为何不利用一下呢
SQL code
DROP TABLE IF EXISTS `t1`;  
create table t1(id int primary key AUTO_INCREMENT,stitle varchar(10),time date);

insert into t1 values (null,'a,b','2011-01-01');
insert into t1 values (null,'c,d','2011-01-02');
insert into t1 values (null,'a','2011-01-03');
insert into t1 values (null,'b,e','2011-01-04');
insert into t1 values (null,'c','2011-01-05');


DROP TABLE IF EXISTS `t2`;  
create table t2(id int primary key AUTO_INCREMENT,name varchar(10));

insert into t2 values (null,'a');
insert into t2 values (null,'b');
insert into t2 values (null,'c');
insert into t2 values (null,'d');
insert into t2 values (null,'e');
insert into t2 values (null,'f');

select t1.id, t2.name as stitle, t1.time from t1, t2 where find_in_set(t2.name, t1.stitle) order by t1.time desc limit 5
<br><font color="#e78608">------解决方案--------------------</font><br>
SQL code


DROP TABLE IF EXISTS `t`;  
create table t(id int primary key AUTO_INCREMENT,stitle varchar(10),time date);

insert into t values ('','a,b,',STR_TO_DATE('2011-01-01','%Y-%m-%d' ));

insert into t values ('','c,d,',STR_TO_DATE('2011-01-02','%Y-%m-%d' ));

insert into t values ('','a, ',STR_TO_DATE('2011-01-03','%Y-%m-%d' ));

insert into t values ('','b,e,',STR_TO_DATE('2011-01-04','%Y-%m-%d' ));

insert into t values ('','c, ',STR_TO_DATE('2011-01-05','%Y-%m-%d' ));



select * from 
(select id,substring(stitle,1,1) as newsitle,time,1 as order1 from t
union all
select id,substring(stitle,3,1) as newsitle,time,2  as order1 from t ) a
where a.newsitle != ' ' order by time desc,order1 asc limit 0,5;


+----+----------+------------+--------+
| id | newsitle | time       | order1 |
+----+----------+------------+--------+
|  5 | c        | 2011-01-05 |      1 |
|  4 | b        | 2011-01-04 |      1 |
|  4 | e        | 2011-01-04 |      2 |
|  3 | a        | 2011-01-03 |      1 |
|  2 | c        | 2011-01-02 |      1 |
+----+----------+------------+--------+ <div class="clear">
                 
              
              
        
            </div>
Statement:
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn