Two implementation methods of jquery ajax submitting form data_jquery

Previously, AJAX was implemented using Javascript scripts one by one, which was very cumbersome. After learning Jquery, I feel that implementing AJAX is not that difficult. Of course, in addition to the Jquery framework, there are other excellent frameworks. Here I will focus on the more popular Jquery. There are two ways to submit a form in Jquery AJAX, one is to submit data via url parameter, and the other is to submit form (as usual, the value of the Form form can be obtained in the background). In the form to be submitted, if there are many elements, it is recommended to submit in the second way. Of course, if you want to practice your "typing skills", it is not a bad idea to submit in the first way. I believe developers don't want to waste their efforts. ! Without further ado, I’ll post an example.
First of all, download the two plug-ins Jquery and Jquery.form, there are many online!
1: Url parameter submission data

Copy code The code is as follows:

Backend code:

Copy code The code is as follows:

if(context. Request.Params["ID"].ToString()!="")
{
Pxt.Logic.SYS.CORP_BASE_INFO cbiL = new Pxt.Logic.SYS.CORP_BASE_INFO();
bool flag= cbiL.checkCorpID(context.Request.Params["ID"].ToString());
if (flag)
{
context.Response.Write("This customer number has been occupied!") ;
}
else
{
context.Response.Write("This customer number is available!");
}
}

Two: Form submits data
Front-end code:

Copy code The code is as follows:

//Must quote
//Must quote

< ;td width="30%" class="tableBg1">Return visit topic:

Customer return visit
Customer name:	< ;asp:TextBox ID="txtF_CorpName" runat="server">
Contact:	:TextBox>
Contact person title:< ;/td>	td>
Contact number:
Return visit time:
Return visit content:
Return visit related documents:
td>	< ;input type="reset" class="button" value="Restore" />