Home >Backend Development >PHP Tutorial > 请问个php正则表达式的用法,求高手帮忙
请教个php正则表达式的用法,求高手帮忙
想做个友情链接的检测方法,检测对方网站是不是有我的网站的友情链接,也就是判断是否有我网站的地址;
例如:我的网站的地址是www.csdn.net,
但是有些网站有时候会在链接里面加个rel="nofollow",这样友情链接就没有意义了;
正则没好好学,问下怎么才能检测出是否加了这个呢?
有好几种情况,例如:
<!-- Code highlighting produced by Actipro CodeHighlighter (freeware) http://www.CodeHighlighter.com/ --><a rel="nofollow" href="http://www.csdn.net">csdn</a>
<!-- Code highlighting produced by Actipro CodeHighlighter (freeware) http://www.CodeHighlighter.com/ --><a target="_blank" rel="nofollow" href="http://www.csdn.net">csdn</a>
<!-- Code highlighting produced by Actipro CodeHighlighter (freeware) http://www.CodeHighlighter.com/ --><a target="_blank" rel="nofollow" href="http://www.csdn.net">csdn</a>
<!-- Code highlighting produced by Actipro CodeHighlighter (freeware) http://www.CodeHighlighter.com/ --><a rel="nofollow" href="http://www.csdn.net" target="_blank">csdn</a>
<!-- Code highlighting produced by Actipro CodeHighlighter (freeware) http://www.CodeHighlighter.com/ --><a href="http://www.csdn.net" target="_blank" rel="nofollow">csdn</a>
<!-- Code highlighting produced by Actipro CodeHighlighter (freeware) http://www.CodeHighlighter.com/ --> $out=strtolower(@file_get_contents(http://www.xxx.com)); if($out){ $out=str_replace("\r\n","",$out); $out=str_replace("\r","",$out); $out=str_replace("\n","",$out); $havelink=preg_match_all('/<a>(.*?)/i', $out, $m); if($havelink||strstr($robots,'nofollow')){ echo "友情链接存在"; } } </a>
$array = csdn <a target="_blank" rel="nofollow" href="http://www.csdn.net">csdn</a> <a target="_blank" rel="nofollow" href="http://www.csdn.net">csdn</a> <a rel="nofollow" href="http://www.csdn.net" target="_blank">csdn</a> HTML; preg_match_all('/(<a.>)/is', $array, $match); if (isset($match[1])) { foreach ($match[1] as $html) { if (stripos($html, 'rel="nofollow"') !== FALSE) echo 'bad!'; break; } } <div class="clear"> </div></a.>