如若根据数据库里的数据显示不同的图片 -PHP Tutorial-php.cn

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如若根据数据库里的数据显示不同的图片

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Jun 13, 2016 pm 01:06 PM

gtimagesincludepngtype

如果根据数据库里的数据显示不同的图片
我有3种类型的数据
是手机端用户可以选择的（图片）
在数据库type字段里显示的是1,2,3 （一共有8种状态用户只能选4个也就是进数据库时只能是只有4个数据如1,2,3,4 或者1,2,3 也可以0,0,0,0 代表什么都没选）。

我想问：
怎么在控制层里面把字段提取出来并在VIEW层里显示相应的图片（图片在本地）
新手回答要详细哦！

------解决方案--------------------
在控制器直接查询这个表就好了，然后取出type字段的数据是个字符串，$c=explode（）转换成数组
在项目里随便建个php文件，然后在里面写个新数组，如
$a=array(
1=>'/images/1.png',
2=>'/images/2.png',
3=>'/images/3.png',
4=>'/images/4.png',
5=>'/images/5.png',
6=>'/images/6.png',
7=>'/images/7.png',
8=>'/images/8.png',
);
include引用创建文件
遍历数组当$c的value值等于$a的k值记录到一个新的二维数组，然后在视图遍历这个数组就得到图片的路径

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