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jQuery getJSON code for processing json data_jquery

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WBOYOriginal
2016-05-16 18:22:331187browse

Html code:

Copy code The code is as follows:









Ashx Handler: If you need to return an object in json format, you need to set the mime type to: "application/json".
Looking at the jQuery source file, you can see that getJSON is implemented like this:
getJSON: function( url, data, callback) {
return jQuery.get(url, data, callback, "json");
},
Copy code The code is as follows:

public void ProcessRequest(HttpContext context)
{
if (context.Request.Params["type"].Equals("ajax"))
{
context.Response.ContentType = "text/plain";
}
else
{
context.Response.ContentType = "application/json";
}
GetInfo(context);
}
public bool IsReusable
{
get
{
return false;
}
}
public void GetInfo(HttpContext context)
{
System.Collections.Generic.List listUser = UserInfoManage .GetUserInfoBySQL("Select Top 5 * From Userinfo");
IsoDateTimeConverter timeConverter = new IsoDateTimeConverter();
timeConverter.DateTimeFormat = "yyyy'-'MM'-'dd' 'HH':'mm': 'ss";
string ResJsonStr = JsonConvert.SerializeObject(listUser, timeConverter);
context.Response.Write(ResJsonStr);
}
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