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提取网址参数的正则表达式
- WBOYOriginal
- 2016-06-13 12:10:111179browse
求一个提取网址参数的正则表达式
<a href='/(kwd0vo45lmdsk055xcz3ov55)/default2.aspx'>here</a>
这部分当中的kwd0vo45lmdsk055xcz3ov55这个提取出来
我用
preg_match_all('/<a\s+href=["|\']?([^>"\' ]+)["|\']?\s*[^>]*>([^>]+)<\/a>/i',$result,$match);<br />不行啊
谢谢大家了
------解决思路----------------------
preg_match_all("/\((.+?)\)/i",$str, $result);<br />echo $result[1];
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