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ajax返回处置
- WBOYOriginal
- 2016-06-13 12:07:08941browse
ajax返回处理
$.get("pai.php",{bbid:bbid,pid:pid,},function(data){
alert("a:"+data);
alert("b:"+data.status);
},"json");
返回值：{"status":1,"info":"\u7ed3\u675f","data":[{"wjc_title":"2\u53a2\u5c0f\u8f7f\u8f66"},{"wjc_title":"3\u53a2\u5c0f\u8f7f\u8f66"}],"jieg":11}
返回值不会处理了，还是对jq不太了解。
我怎么把返回值data里的wjc_title的值插入到div里的li里，有几个wjc_title就循环几个
- 插入值
- 插入值1
- 插入值2
------解决思路----------------------
<script type="text/javascript"><br /><br /> var data = {"status":1, "info":"\u7ed3\u675f", "data":[<br /> {"wjc_title":"2\u53a2\u5c0f\u8f7f\u8f66"},<br /> {"wjc_title":"3\u53a2\u5c0f\u8f7f\u8f66"}<br /> ], "jieg":11};<br /><br /><br /> function insert(data) {<br /><br /> if (!jQuery.isArray(data.data)) return false;<br /><br /> var $target = jQuery('div.row').empty();<br /><br /> for (var i = 0; i < data.data.length; ++i) {<br /><br /> $target.append("<ul><li>" + data.data[i].wjc_title + "</li></ul>");<br /> }<br /><br /> return true;<br /> }<br /><br /> insert(data);<br /> <br /></script>------解决思路----------------------
<br /><!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN"><br /><html><br /> <head><br /> <meta http-equiv="content-type" content="text/html; charset=utf-8"><br /> <title> New Document </title><br /> <script src="//code.jquery.com/jquery-1.11.0.min.js"></script><br /> </head><br /><br /> <body><br /><br /> <div class="row"><br /> <ul><br /> <li>插入值1</li><br /> </ul><br /> <ul><br /> <li>插入值2</li><br /> </ul><br /> <div><br /><br /> <script type="text/javascript"><br /> var bbid = 1;<br /> var pid = 1;<br /> <br /> $.get("pai.php",{bbid:bbid,pid:pid,},function(data){<br /> for(var i=0; i<data.data.length; i++){<br /> $($('.row').find('li').get(i)).html(data.data[i].wjc_title);<br /> }<br /> },"json");<br /> </script><br /><br /> </body><br /></html><br />pai.php
<br /><?php<br />echo '{"status":1,"info":"\u7ed3\u675f","data":[{"wjc_title":"2\u53a2\u5c0f\u8f7f\u8f66"},{"wjc_title":"3\u53a2\u5c0f\u8f7f\u8f66"}],"jieg":11}';<br />?><br />------解决思路----------------------
本末倒置！
php 作为服务端，理应按客户端的要求返回数据
你连客户端代码都不会写，那还 ajax 做什么？
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