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php基础+jquery基础,该怎么解决
- WBOYOriginal
- 2016-06-13 11:50:43858browse
php基础+jquery基础
1.编写一个函数，使它可以根据传入的2个年周号，返回它们之间的周数(包括传入的这两周)
2.用JQuery实现根据所选的日期范围动态增加那范围内每一天的金额输入框，并在最后面显示出所有天金额的累加值
------解决方案--------------------
1.
function between($one,$tow){<br /> return abs(date('W',$one) - date('W',$two));<br />}------解决方案--------------------
2.
<html><br /> <head><br /> <title>Demo</title><br /> <script type="text/javascript" src="jquery-1.4.2.min.js"></script><br /><br /> </head><br /> <br /> <body><br /> <input type="text" id="time" value="2014/01/01-2014/01/10"><br /> <div id="timeShow"></div><br /> <span id='countSpan'></span><br /> <input type="button" value="结算" id='count'><br /> <script type="text/javascript"><br /> $(function(){//jquery开始 必不可少<br /> <br /> var time = $("#time").val();<br /> var timeArr = time.split('-');<br /> var date1 = new Date(timeArr[0]);<br /> var date2 = new Date(timeArr[1]);<br /> var miao = Math.abs(date2.getTime() - date1.getTime());<br /> var day = parseInt(miao / (1000 * 60 * 60 * 24));//计算相差天数<br /><br /> var input = '';<br /> for(var i=0;i<=day;i++){<br /> input += '<input type="text" id="day_'+i+'" class="day">';<br /> }<br /> $("#timeShow").html(input);<br /><br /> $("#count").click(function(){<br /> var total = 0;<br /> $(".day").each(function(){<br /> var val = $(this).val();<br /> val = $.trim(val);<br /> val = isNaN(val) <br><font color='#FF8000'>------解决方案--------------------</font><br> val == "" ? 0 : val;<br /> total += parseFloat(val);<br /> })<br /> $("#countSpan").html(total);<br /> })<br /> <br /> })<br /> <br /> </script><br /> </body><br /></html>
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