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正则截取html中的一段,该如何解决

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2016-06-13 11:45:41983browse

正则截取html中的一段

<br /><html><br /><body><br />.........<br />.........<br /><ul class="style5"><br /><li><a href="/profiles/83291221"><img src="/static/imghwm/default1.png"  data-src="/images/252754752"  class="lazy"   alt="标题标题" />标题标题</a></li><br /><li><a href="/profiles/83291221"><img src="/static/imghwm/default1.png"  data-src="/images/252754752"  class="lazy"   alt="标题标题" />标题标题</a></li><br /><li><a href="/profiles/83291221"><img src="/static/imghwm/default1.png"  data-src="/images/252754752"  class="lazy"   alt="标题标题" />标题标题</a></li><br /></ul><br />........<br />........<br /><br /></body><br /><br /></html><br /><br /><br />


这样的循环  我要截取第一条,多的不要

  • 正则截取html中的一段,该如何解决标题标题
  •  中的"83291221" "标题标题"  这两个,另外把这两个转换成变量  求大神解@@@



    ------解决方案--------------------
    <br />preg_match_all("<br><font color='#FF8000'>------解决方案--------------------</font><br><li><a href=[\"\']\/(.*)\/(.*)[\"\']><img (.*) alt="正则截取html中的一段,该如何解决" >(.*)</a></li><br><font color='#FF8000'>------解决方案--------------------</font><br>U", $str, $out);<br />$a = $out[2][0];<br />$b = $out[4][0];<br />echo "a::$a , b::$b";<br />

    ------解决方案--------------------
    preg_match('#<ul class="style5">(.+?)</ul>#s',$s,$m);<br />preg_match('#<li><a href="/profiles/(\d+)"><img [^ alt="正则截取html中的一段,该如何解决" >]+>(.+?)</a></li>#s',$m[1],$ar);<br />print_r($ar);
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