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解析php中如何调用用户自定义函数

Jun 13, 2016 am 11:41 AM
phpuserexamplefunctionhowuserkindcustomizeparsetransfer

先放上来别人的例子吧:
call_user_func函数类似于一种特别的调用函数的方法,使用方法如下:   

复制代码 代码如下:


function a($b,$c)   
{   
echo $b;   
echo $c;   
}   
call_user_func('a', "111","222");   
call_user_func('a', "333","444");   
//显示 111 222 333 444   
?>   

  
调用类内部的方法比较奇怪,居然用的是array,不知道开发者是如何考虑的,当然省去了new,也是满有新意的:   

复制代码 代码如下:


class a {   
function b($c)   
{   
echo $c;   
}   
}   
call_user_func(array("a", "b"),"111");   
//显示 111   
?>   

  
call_user_func_array函数和call_user_func很相似,只不过是换了一种方式传递了参数,让参数的结构更清晰:   

复制代码 代码如下:


function a($b, $c)   
{   
echo $b;   
echo $c;   

}   
call_user_func_array('a', array("111", "222"));   
//显示 111 222   
?>   

  
call_user_func_array函数也可以调用类内部的方法的   

复制代码 代码如下:


Class ClassA   
{   

function bc($b, $c) {   
     $bc = $b + $c;   
echo $bc;   
}   
}   
call_user_func_array(array('ClassA','bc'), array("111", "222"));   

//显示 333   
?>   

 
call_user_func函数和call_user_func_array函数都支持引用,这让他们和普通的函数调用更趋于功能一致:   

复制代码 代码如下:


function a($b)   
{   
$b++;   
}   
$c = 0;   
call_user_func('a', $c);   
echo $c;//显示 1   
call_user_func_array('a', array($c));   
echo $c;//显示 2  


另:call_user_func函数和call_user_func_array函数都支持引用。

复制代码 代码如下:


function increment(&$var)
{
    $var++;
}
$a = 0;
call_user_func('increment', $a);
echo $a; // 0
call_user_func_array('increment', array(&$a)); // You can use this instead
echo $a; // 1
?>

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