PHP采集程序有关问题

PHP采集程序问题

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这两段是我采集过来的，采集两个产品页面，我就想要产品图片的地址
http://ec2.images-amazon.com/images/I/418Qdk6bctL._SL500_AA280_.jpg
http://ec2.images-amazon.com/images/I/51bsLAswKVL._SL500_AA280_.jpg

整个页面的代码很多，我就是想要这个图片
http://ec2.images-amazon.com/images/I/
._SL500_AA280_.jpg
以上两段每个页面都是一样的，请问怎么过滤我想要的这个图片地址

分享到：
------解决方案--------------------
preg_match_all('#src="(http://ec2\.images-amazon\.com/images/I/[a-z\d]+\._SL500_AA280_\.jpg)"#is',$s,$m);
print_r($m[1]);