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HomeBackend DevelopmentPHP TutorialPHP POST下传,无法读取下传的字符串

PHP POST上传,无法读取上传的字符串
本地c#写的 用WebClient类http://1.liuruitao.sinaapp.com/test.php?name={0}通过这个url上传的,网页那边

 if($_SERVER['REQUEST_METHOD']=="POST")   
{
  // $s=json_encode($_post)

    $s=$_GET["name"];
     echo "hello world!!";
    echo $_POST["name"];
    $conn=mysql_connect(SAE_MYSQL_HOST_M.':'.SAE_MYSQL_PORT,SAE_MYSQL_USER,SAE_MYSQL_PASS);
    if(!$conn)
    die("connect fail".mysql_error());
     mysql_select_db('app_liuruitao',$conn);
     $sql = "insert into $db values ('3344556677',$s,3,'4',5,'6','7','8','9')";
     mysql_query($sql,$conn);//借SQL语句插入数据
    mysql_close();//关闭MySQL连接
   echo "insert success";
}
就是无法正确获取上传的name里面的字符串插入到数据库中,大家帮帮忙谢谢了


------解决方案--------------------
$sql = "insert into $db values ('3344556677',$s,3,'4',5,'6','7','8','9')";
如果 $s 无值,那么实际执行的 SQL指令为
insert into 表名 values ('3344556677',,3,'4',5,'6','7','8','9')
显然是错误的
可通过
mysql_query($sql,$conn) or die(mysql_error());
知道这种情况是否存在
另外
$sql = "insert into $db values ('3344556677',$s,3,'4',5,'6','7','8','9')";
应写作
$sql = "insert into $db values ('3344556677','$s',3,'4',5,'6','7','8','9')";
以免意外的发生
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