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php mongodb 注入

Jun 13, 2016 am 10:56 AM
mongodbphpDownunderintroduceprincipleandPostmethodinjectionof

 


下面就介绍下php+mongodb注入的方法和原理

其中一篇帖子说:login.php?username=admin&passwd[$ne]=1就有可能注入,刚看的时候,我感觉挺纳闷的,这个怎么就存在注入漏洞了呢,终于从这篇帖子http://hi.baidu.com/hi_heige/item/ce93ce926dede4f428164747中发现了原因。因为PHP是可以直接提交array的,也就是说提交的是含有“$ne”索引的数组,我做了个demo:


[php]
$passwd=$_GET["passwd"]; 
var_dump($passwd); 

$passwd=$_GET["passwd"];
var_dump($passwd);
测试结果为:

array(1) { ["$ne"]=> string(1) "1" }

 


这样的话


[php]
$collection->find(array( 
    "username" => "admin", 
    "passwd" => array("$ne" => 1) 
)); 

$collection->find(array(
    "username" => "admin",
    "passwd" => array("$ne" => 1)
));
就变为了:


[php]

$collection->find(array(      "username" => "admin",      "passwd" => array("$ne" => 1)  ));  $collection->find(array(
    "username" => "admin",
    "passwd" => array("$ne" => 1)
));


如果把链接改成这种(username=[$ne]=1&passwd[$ne]=1)的话,那么会把所有的用户信息都获取过来

解决这个bug的方法为在获取参数后都把参数强制转换成string类型下:

[php]
$collection->find(array( 
    "username" => (string)$_GET['username'], 
    "passwd" => (string)$_GET['passwd'] 
)); 

$collection->find(array(
    "username" => (string)$_GET['username'],
    "passwd" => (string)$_GET['passwd']
));这个与执行下面的mysql语句是一样的道理了,都注入了


[php]

mysql_query("SELECT * FROM collection 
    WHERE username="admin", 
    AND passwd!=1 

mysql_query("SELECT * FROM collection
    WHERE username="admin",
    AND passwd!=1
我做了个demo测试了下,果然好使。

 

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