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php善用正则表达式 处理字符串中需不要的值

Jun 13, 2016 am 10:50 AM
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  今天在采集莫网址的图片的时候,由于自己最后都会讲图片分辨率改为320*480,而原先的图片中存在有关于像素的信息。

     如:清晰小屋(320*480)壁纸

     那么最后我要留下的是“清晰小屋壁纸”,该怎么办呢?

    首先我们应该立马想到,先查找字符串,在去掉此字符串。

    嗯,首先我也是这么想的,定义一个数组,其中存了几个字符串,如(320*480)、(480*640)等,不过后来发现,其中还有其他类型的如(320*234)之流的,那么我全列出来也不是不可能的,只不过是时间的问题。但是我们不这么做,是在太没意思了。这样弄得话,估计半天就过去了,而且弄得自己很不爽。

   那么该这么办呢?

   首先观察多个数据,我们发现,其中有应该要有“*”,这个必须得知道的,否则没有要去的值也弄进来,加大计算机的工作量了。

   那么就来了一个:

[php] 
if(strchr($title, "*")) 
      { 
 用来判断字符串中是否包含"*";
 如果包含了,那么里面一定有我们要去掉的东西,接下来该怎么办,找出要去掉的字符串,然后用NULL替换?显然不能在像上面的方式找了。

而我用了字符串切割的方式:

[php] 
$arr=split('([\(]*)[0-9]+\*[0-9]+([\)]*)',$title);//*一定要进行转义 
        $title = $arr[0].$arr[1]; 
其中([\(]*)[0-9]+X[0-9]+([\)]*)为正则表达式,
([\(]*)表示可能存在(

[0-9]+表示至少存在一个0到9的数字

[php] 
\*存在"*" 
那么上面的 (320*480) 很简单的找出来了。 
一下是测试程序 

[php] 

<?php  <br />
  <br>
$title="清晰小屋(320*480)壁纸"; <br>
 <br>
if(strchr($title, "*")) <br>
      { <br>
        $arr=split('([\(]*)[0-9]+\*[0-9]+([\)]*)',$title);//*一定要进行转义 <br>
        $title = $arr[0].$arr[1]; <br>
                echo $title; <br>
      } <br>
?> 
<br>
作者:wolinxuebin						
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