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关于目录遍历,结果为树形结构的有关问题,请上

WBOY
WBOYOriginal
2016-06-13 10:46:01906browse

关于目录遍历,结果为树形结构的问题,请高手指点下
我想递归遍历一个目录,然后让结果呈树形结构展示出来,请高手指点下。下面是遍历函数

PHP code
<!--Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/--><?phpecho "<pre class="brush:php;toolbar:false">";$path = "E:/ProgramBack";function ERGFile($path){            $AllFiles = scandir($path);    foreach($AllFiles as $key=>$file){                if($file == "." || $file == ".."){                        continue;                    }                if(is_dir($path."/".$file)){            echo $path."/".$file." -- DIR <br>";            ERGFile($path."/".$file);        }else{            echo $path."/".$file."<br>";        }    }        }ERGFile($path);?>


如何让他以树形结构显示呢?
a -- dir
 a.tx
 a1.exe
 a1 -- dir
  aa.txt
  bb.exe
b --dir
 b2 -- dir
 b3 -- dir
  b3b.txt
  b4g.exe
..........

------解决方案--------------------
在 echo 后面插入 str_repeat(' ', substr_count($path, '/')) .
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