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PHP的效能已经实现,却总是报错

WBOY
WBOYOriginal
2016-06-13 10:32:47682browse

PHP的功能已经实现,却总是报错
代码的目的是实现图片上传到指定目录,并且在mysql中记录图片路径。
现在目的已经实现,可是页面总是报错,

报错内容就是第二行:

PHP code
<!--Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/--><?phpif ($_GET['action'] == "save"){  //这行报错:Notice: Undefined index: action in D:\xampp\htdocs\upload.php on line 2include_once('MYDBconn.php');include_once('UPclass.php');$titles=$_POST['title'];$images=$uploadfile;if($titles == "")echo"<Script>window.alert('No title');history.back()";$sql="insert into product(title,pic) values('$titles','$images')";$result=mysql_query($sql,$conn);echo"<script>window.alert('congratunations');location.href='upload.php'</script>";}?><title>images transfer</title>    
 
titles:
Images:
 


麻烦指教一番,究竟是哪里出错了,谢谢

------解决方案--------------------
if ( isset($_GET['action']) && $_GET['action'] == "save" )

------解决方案--------------------
上个问题帖子答过你了,在置顶的基础问题帖子里也有提到这个问题
这是一个提示不是错误

在传递过来的参数 包括post 在新版本,应该是5.3X的某个版本后需要做一个

isset进行判断,否则就会出现这个提示,当然你可以调整出错提示的等级来屏蔽这样的提示.
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