SQL语句写法的问题
$search1 = "SELECT classroom_id,building_id FROM use2
WHERE (time = '{$time}')
AND (building_id = '{$building_id}')
AND (lesson_id LIKE '$lesson_id')";
$result1 = mysql_query($search1, $con);
$row = mysql_fetch_array($result1);
$search2 = "SELECT * FROM classroom2
WHERE (building_id = '{$building_id}')
AND * NOT IN
(SELECT * FROM classroom2
WHERE (building_id = '{$building_id}')
AND (classroom_id = '${row['classroom_id']}')";
$result2 = mysql_query($search2);
while($row = mysql_fetch_array($result2))
{}
显示mysql_fetch_array() expects parameter 1 to be resource, boolean given in D:\xampp\htdocs\search_free2.php
use2里面存储了一些课室的使用信息,包括每节课使用的时间,课室号,哪一栋等等
然后现在实现的是输入栋号,时间查找空课室的功能,我先看按我输入的信息,看在这样的时间个栋号在use2里面有没有某些课室相关的信息,如果全部都没有相关的实现没有问题。
这是如果没有的实现,有点问题。我是想如果没有,就先把没有相关信息的课室找出来,再处理有相关信息的课室。但是找没有相关信息的课室,就显示如上错误,请指教!
------解决方案--------------------
$result1 = mysql_query($search1, $con) or die(mysql_error());
$result2 = mysql_query($search2) or die(mysql_error());
都提示什么错误。

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