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php通过表单提交参数查询解决方案

WBOY
WBOYOriginal
2016-06-13 10:21:521331browse

php通过表单提交参数查询
如题 想做个简单的查询系统:
现在搞了个没有表单的,代码如下:

PHP code
<!--Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/--><?php $con = mysql_connect("localhost","username","password");if (!$con)  {  die('Could not connect: ' . mysql_error());  }mysql_select_db("cbd", $con);$result = mysql_query("SELECT date,ip,  count(ip) as count FROM syn_number WHERE date like '%05-08%' group by ip order by count desc limit 10");echo "<table border='1'><tr>
<th>date</th>
<th>ip</th>
<th>number</th>
</tr>";while($row = mysql_fetch_array($result))  {  echo "<tr>";  echo "<td>" . $row['FirstName'] . "</td>";  echo "<td>" . $row['LastName'] . "</td>";  echo "</tr>";  }echo "";mysql_close($con);?>


现在想把这段代码sql语句中的 05-08 和最后的limit 10 数字10 改为用表单提交,每次我可以输入
0508最好是可以输入一个范围 比如0508到0510 这样

请问该如何实现?

用表单的话 是要再搞个html文件了?

------解决方案--------------------
$limit = ' LIMIT ' . $_POST['start'] . ',' . $_POST['end'];

$sql = "SELECT date,ip, count(ip) as count FROM syn_number WHERE date like '%05-08%' group by ip order by count desc $limit";

$result = mysql_query($sql);
-----------

html

Limit:


------解决方案--------------------
SELECT date,ip, count(ip) as count FROM syn_number
你从数据只获得三列数据 date, ip, count 哪来的FirstName,SecondName,LastName?
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