


Why do all values in the map point to the same memory address when using for range loop to loop through slices in Go?
Traps between for...range
loop and map in Go language
This article analyzes a common Go programming problem, which involves the usage of structures, slices, and maps, and explains why when using for...range
loop to traverse slices, all values in the map point to the same memory address. Understanding this problem is crucial to mastering the memory management and reference types of Go.
Problem description:
The following code snippet demonstrates the problem:
type student struct { name string age int } func main() { m := make(map[string]*student) stus := []student{ {name: "pprof.cn", age: 18}, {name: "test", age: 23}, {name: "Blog", age: 28}, } for _, stu := range stu { m[stu.name] = &stu } for k, v := range m { fmt.Println(k, "=>", v.name) } }
The run results show that all v.name
values are "blog". This is because when the for...range
loop traverses the slice, stu
variable is a temporary variable inside a loop, and its memory address points to the same memory location in each iteration. Therefore, m[stu.name] = &stu
actually points all values in the map to the memory address of the same student
structure, and this address points to the last element "blog" after the loop ends.
Solution:
To avoid this problem, you should use the index of the slice in the loop to get the address of the element as shown below:
for i := range stus { m[stus[i].name] = &stus[i] }
This method ensures that the address of each student
structure is independent, thus avoiding the problem that all values point to the same memory address.
Summarize:
This problem reveals the characteristics of the Go language for...range
loop and the behavior of reference types. Understanding the life cycle of temporary variables in for...range
loop, and how to properly handle reference types are essential for writing efficient and error-free Go code. Properly using indexes to access slice elements can avoid such memory management traps.
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