What is the execution order of the init() function in Go language?

Detailed explanation of the execution order of the init() function in Go language

The Go language init() function is used to perform some necessary operations when package initialization. A Go file can contain multiple init() functions, which are executed in the order they appear in the source file. This allows developers to accurately control the steps of package initialization to ensure the correct handling of dependencies.

Let's understand it with an example:

 package main

import "fmt"

func main() {
    hello()
}

func hello() {
    fmt.Println("hello")
}

func init() {
    fmt.Println("init 3")
}

func init() {
    fmt.Println("init 2")
}

func init() {
    fmt.Println("init 1")
}

This code contains three init() functions. After running the program, the output will be:

 <code>init 1 init 2 init 3 hello</code>

This clearly shows that the order init() function is exactly the same as the order in which it appears in the code. Therefore, you can use this feature to arrange the steps for package initialization, such as initializing the database connection first, loading configuration files, etc. Understanding the execution order of init() function is crucial to writing a clear structure and easy to maintain Go program.

The above is the detailed content of What is the execution order of the init() function in Go language?. For more information, please follow other related articles on the PHP Chinese website!