


Go function parameter passing: Why does pointer variable remain unchanged after being modified inside the function?
Pointer variable trap in Go function parameter passing: Why is it invalid to modify external variables in the function?
This article analyzes common problems about pointer variable assignment in a Go language program. The program tries to modify the pointer variable to the database connection object inside the function, but the variable in the main function has not been modified.
The following code snippet shows this problem:
var db *sql.DB func main() { initDB(db) fmt.Println(db) // Print<nil> } func initDB(db *sql.DB) { var err error db, err = sql.Open("mysql", "root:123456@tcp(127.0.0.1:3306)/data") checkErr(err) db.SetMaxOpenConns(100) db.SetMaxIdleConns(100) db.SetConnMaxLifetime(time.Minute * 3) if err := db.Ping(); err != nil { checkErr(err) } fmt.Println(db) // What is printed here is the correct value} func checkErr(err error) { if err != nil { panic(err) } }</nil>
db
printed by main
function is still nil
, and the initDB
function has successfully connected to the database. This is because the function parameter passing mechanism of Go language is value passing. Even if the parameter is a pointer type, the passed copy of the pointer value.
In the initDB
function, db, err := sql.Open(...)
creates a new *sql.DB
object and assigns the object to the local variable db
inside initDB
function. This does not modify the pointing of the db
variable in the main
function. After the initDB
function ends, its local variable db
is destroyed, and db
in the main
function is still nil
.
To correctly modify the db
variable in the main
function, you need to use a pointer to a pointer, or use a pointer receiver in the initDB
function. Here is how to use pointers to solve this problem:
var db *sql.DB func main() { initDB(&db) fmt.Println(db) // The correct value will be printed now} func initDB(db **sql.DB) { var err error *db, err = sql.Open("mysql", "root:123456@tcp(127.0.0.1:3306)/data") checkErr(err) (*db).SetMaxOpenConns(100) (*db).SetMaxIdleConns(100) (*db).SetConnMaxLifetime(time.Minute * 3) if err := (*db).Ping(); err != nil { checkErr(err) } fmt.Println(*db) // What is printed here is the correct value} func checkErr(err error) { if err != nil { panic(err) } }
By passing the address of db
( &db
), the initDB
function can directly modify the pointing of the db
variable in the main
function.
The above is the detailed content of Go function parameter passing: Why does pointer variable remain unchanged after being modified inside the function?. For more information, please follow other related articles on the PHP Chinese website!

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