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Python list comprehension provides a concise way of writing code, which allows you to simultaneously calculate the value of an expression and assign it to a variable. Using the walrus operator (:=), we can optimize the code:
square_cubes = [res if (res := n**2) % 9 == 0 or res % 4 == 0 else n**3 for n in range(1, 11)] print(square_cubes) # 输出: [1, 4, 9, 16, 125, 36, 343, 64, 81, 100]
Here, we store the res
variables to store the calculation results n**2
and reuse them in subsequent code to avoid repeated calculations.
List comprehension supports nested loops, and there is no limit on the number of loops. But it should be noted that the loop sequence must be consistent with the original code. You can also add optional for
conditions after each for
cycle. The list comprehension structure of nested if
loops is as follows: for
[ <表达式> for <元素a> in <可迭代对象a> (可选 if <条件a>) for <元素b> in <可迭代对象b> (可选 if <条件b>) for <元素c> in <可迭代对象c> (可选 if <条件c>) ... ]The following example demonstrates a list comprehension of nested loops for generating multiplication tables:
multiplications = [] for i in range(1, 4): for n in range(1, 11): multiplications.append(i*n) print(multiplications) # 输出: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 3, 6, 9, 12, 15, 18, 21, 24, 27, 30]Convert it to a list comprehension:
multiplications = [i*n for i in range(1,4) for n in range(1,11)] print(multiplications) # 输出: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 3, 6, 9, 12, 15, 18, 21, 24, 27, 30]List comprehension can also be used to flatten nested lists:
matrix = [ [1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], ] flatten = [n for row in matrix for n in row] print(flatten) # 输出: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12]Nested list comprehension
Use normal loop:
matrix = [ [1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], ] transpose = [] for i in range(4): temp = [] for row in matrix: temp.append(row[i]) transpose.append(temp) print(transpose) # 输出: [[1, 5, 9], [2, 6, 10], [3, 7, 11], [4, 8, 12]]Use nested list comprehension:
matrix = [ [1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], ] transpose = [[row[n] for row in matrix] for n in range(4)] print(transpose) # 输出: [[1, 5, 9], [2, 6, 10], [3, 7, 11], [4, 8, 12]]Set and dictionary derivation
squares_cubes = {n: n**2 if n%2 == 0 else n**3 for n in range(1,11)} print(squares_cubes) # 输出: {1: 1, 2: 4, 3: 27, 4: 16, 5: 125, 6: 36, 7: 343, 8: 64, 9: 729, 10: 100}Set derivation is used to create unordered sets:
import random non_multiples = {n for n in random.sample(range(0, 1001), 20) if n not in range(0, 1001, 9)} print(non_multiples) # 输出 (示例): {3, 165, 807, 574, 745, 266, 616, 44, 12, 910, 336, 145, 755, 179, 25, 796, 926}Summary
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