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How to Deserialize JSON into Dynamic Objects in C#?

Linda Hamilton
Linda HamiltonOriginal
2025-02-03 01:36:10470browse

How to Deserialize JSON into Dynamic Objects in C#?

The dynamic JSON counter -serialization in the c#

C# allows the adaptation of JSON content into a dynamic object without creating a class for data binding.

Use json.net

JSON.NET provides a simple way to sequence JSON's derivatives into dynamic objects:

Use newtonsoft.json.linq

<code class="language-csharp">dynamic stuff = JsonConvert.DeserializeObject("{ 'Name': 'Jon Smith', 'Address': { 'City': 'New York', 'State': 'NY' }, 'Age': 42 }");

string name = stuff.Name;
string address = stuff.Address.City;</code>

newtonsoft.json.linq also allows dynamic JSON back serialization:

Query dynamic json

<code class="language-csharp">dynamic stuff = JObject.Parse("{ 'Name': 'Jon Smith', 'Address': { 'City': 'New York', 'State': 'NY' }, 'Age': 42 }");

string name = stuff.Name;
string address = stuff.Address.City;</code>
Dynamic objects allow the JSON attribute to query JSON attributes like the C# attribute of this machine:

More information

For details about querying dynamic JSON in C#, see:
<code class="language-csharp">string city = stuff.Address.City;</code>

Document: Use dynamic query json

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