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How to Convert a String with Fractional Seconds (e.g., '2009-05-08 14:40:52,531') to a DateTime Object?

Susan Sarandon
Susan SarandonOriginal
2025-02-02 03:26:10819browse

How to Convert a String with Fractional Seconds (e.g.,

Parsing Strings with Fractional Seconds into DateTime Objects

The DateTime.Parse method in many programming languages may struggle with date strings containing fractional seconds, especially if the format deviates from the standard. This article demonstrates how to accurately convert such strings using custom formatting.

The Challenge:

Consider a date string like "2009-05-08 14:40:52,531". The comma separating the seconds and milliseconds presents a parsing problem for default methods.

The Solution:

The key is to employ a function that allows specifying a custom format string. This string precisely defines the structure of the input date string. The example below uses a hypothetical DateTime.ParseExact function (the exact function name and arguments might vary slightly depending on your programming language):

<code>DateTime myDate = DateTime.ParseExact("2009-05-08 14:40:52,531", "yyyy-MM-dd HH:mm:ss,fff", CultureInfo.InvariantCulture);</code>

Here's a breakdown of the custom format string "yyyy-MM-dd HH:mm:ss,fff":

  • yyyy: Four-digit year (e.g., 2009)
  • MM: Two-digit month (e.g., 05)
  • dd: Two-digit day (e.g., 08)
  • HH: Two-digit hour (24-hour format) (e.g., 14)
  • mm: Two-digit minute (e.g., 40)
  • ss: Two-digit second (e.g., 52)
  • ,: The comma acts as the literal separator between seconds and milliseconds.
  • fff: Three-digit milliseconds (e.g., 531)

By explicitly defining the comma as a separator, the parser correctly interprets the fractional part as milliseconds. This technique ensures reliable conversion of date strings with non-standard formats into DateTime objects. Remember to consult your programming language's documentation for the precise syntax of its custom date/time parsing functions.

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