How to Convert Integers to Hexadecimal and Back in C#?

The mutual conversion of the integer and the sixteen -proof string in C#

Question:

How to seamlessly converts the integer into a hexadecimal string in C#, and vice versa?

Background:

In order to improve the user experience, you can modify the database that stores the user ID as an integer, and display the ID with a shorter value of the hexadecimal equivalent.

Solution:

The key to this conversion is to use the .tring () method provided by INT type.

Our integer to hexades:

1. To convert the integer into a hexadecimal string, please use the .tring () method with a "X" format description symbol. For example:

   This will assign the hexadecimal string "B76" to HEXVALUE.

   <code class="language-csharp">int intValue = 2934;
   string hexValue = intValue.ToString("X"); </code>

   Sixteen -to -Improven:

2. To convert the hexadecimal string back to its integer representation form, we can use the Int.Parse () method and the numberstyles.hexnumber style. For example:

   This will assign an integer 2934 to Intagain.

   <code class="language-csharp">string hexValue = "B76";
   int intAgain = int.Parse(hexValue, System.Globalization.NumberStyles.HexNumber);</code>

   Additional description:

To get a hexadecimal string that accurately contains four -digit numbers (no matter how much you value), please use .tring ("x4").

For a lowercase hexadecimal number, please use .tring ("X") or .tring ("x4").

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