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Json.NET: Deserializing Objects with Non-Default Constructors
Json.NET typically uses the default constructor for deserialization. However, if your class has a non-default constructor that's necessary for other reasons, you can still use Json.NET to deserialize using your preferred constructor.
Using the [JsonConstructor]
Attribute
The simplest solution is to mark your desired constructor with the [JsonConstructor]
attribute. This tells Json.NET to use this constructor during deserialization. Make sure the constructor parameter names match the JSON property names (case-insensitive).
<code class="language-csharp">[JsonConstructor] public Result(int? code, string format, Dictionary<string, string> details = null) { // ... }</code>
Creating a Custom JsonConverter
If you can't modify the source code directly, you can create a custom JsonConverter
.
<code class="language-csharp">class ResultConverter : JsonConverter { // ... implementation details ... }</code>
Then, add the converter to your serializer settings:
<code class="language-csharp">JsonSerializerSettings settings = new JsonSerializerSettings(); settings.Converters.Add(new ResultConverter()); Result result = JsonConvert.DeserializeObject<Result>(jsonText, settings);</code>
This approach provides more control over the deserialization process without altering the original class definition. The JsonConverter
allows for flexible object creation and property population.
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