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How Can I Deserialize JSON Objects with Non-Default Constructors Using Json.net?

Susan Sarandon
Susan SarandonOriginal
2025-01-29 16:41:10559browse

How Can I Deserialize JSON Objects with Non-Default Constructors Using Json.net?

Json.NET: Deserializing Objects with Non-Default Constructors

Json.NET typically uses the default constructor for deserialization. However, if your class has a non-default constructor that's necessary for other reasons, you can still use Json.NET to deserialize using your preferred constructor.

Using the [JsonConstructor] Attribute

The simplest solution is to mark your desired constructor with the [JsonConstructor] attribute. This tells Json.NET to use this constructor during deserialization. Make sure the constructor parameter names match the JSON property names (case-insensitive).

<code class="language-csharp">[JsonConstructor]
public Result(int? code, string format, Dictionary<string, string> details = null)
{
    // ...
}</code>

Creating a Custom JsonConverter

If you can't modify the source code directly, you can create a custom JsonConverter.

<code class="language-csharp">class ResultConverter : JsonConverter
{
    // ... implementation details ...
}</code>

Then, add the converter to your serializer settings:

<code class="language-csharp">JsonSerializerSettings settings = new JsonSerializerSettings();
settings.Converters.Add(new ResultConverter());

Result result = JsonConvert.DeserializeObject<Result>(jsonText, settings);</code>

This approach provides more control over the deserialization process without altering the original class definition. The JsonConverter allows for flexible object creation and property population.

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